plzzz.. can any1 solve this..

two vessels contain a mixture of acid and water in one vessel there is twice as much acid as water and in 2nd vessel there is 3 times as much water as acid find how much liter of mixture must be drawn from each vessel to fill a 3rd vessel of capacity 15 liter in order that it content must do half acid and half water

Easy Math Editor

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Comments

Take 9 litesr of mixture 1 ( H2O:Acid:1:2) and mix with 6 liters of mixture 2( H2O:Acid:3:1) and produce a 15 liter of half water half acid.

Venture HI - 6 years, 3 months ago

can u xplain in more depth.... plzz

Nimit Dave - 6 years, 3 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$