I'm not sure for this. If we put on a line balloons and clip them to the table (almost going to pop if you blow more air) and pop the first one will the others pop too? I think they will. Because i'm not sure would you tell me?
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I think they might have popped the other ones like in the domino effect. If they are close enough then when you pop one It will explode (right) and due to the proximity when the balloon extends (or explodes) the exploding balloon would most probably trigger the other balloon which will trigger another balloon like in a domino effect. This is what I think. I am not so sure
I tried it but only the next one popped. But I think the reason behind it is that I might not have blown the balloons to their maximum limit. If the situation were ideal I think all of them will pop.
Under ideal conditions like if there is no air resistance, friction between the balloons all the balloons will pop if the first one will pop. The reason behind this lies in the fact that the energy is conserved. If the first balloon pops up it means that it had gained some energy and now by law of conservation of energy as friction and air resistance are absent the released energy (when the balloon pops up) should be transmitted to the next balloon which will be enough to pop it up and this sequence continues till the last balloon.
But in practical this will not happen because of the presence of friction and air resistance which absorbs the released energy when the first balloon pops up. But if the applied force is large enough to overcome these forces all balloons may pop up.
This question is very interesting and I liked it so much. Why can't you post this as a question. If you want assistance I will help you. If you agree I myself will post the problem. I have already framed the question and was now searching for the suitable picture.
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Good !! I have finded two more. But I am waiting till next week because I think that there are enough problems from Rohit Gupta and Pranshu Gaba in physics category to be featured in next week problems of the week. So, I will post the question on Monday or soo as I want this question to be featured.
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to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
I think they might have popped the other ones like in the domino effect. If they are close enough then when you pop one It will explode (right) and due to the proximity when the balloon extends (or explodes) the exploding balloon would most probably trigger the other balloon which will trigger another balloon like in a domino effect. This is what I think. I am not so sure
Hmm.. that's interesting. I have a lot of balloons at home. Maybe I'll try this today. Whatever happens I'll let you know.
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Thanks!
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I tried it but only the next one popped. But I think the reason behind it is that I might not have blown the balloons to their maximum limit. If the situation were ideal I think all of them will pop.
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Under ideal conditions like if there is no air resistance, friction between the balloons all the balloons will pop if the first one will pop. The reason behind this lies in the fact that the energy is conserved. If the first balloon pops up it means that it had gained some energy and now by law of conservation of energy as friction and air resistance are absent the released energy (when the balloon pops up) should be transmitted to the next balloon which will be enough to pop it up and this sequence continues till the last balloon.
But in practical this will not happen because of the presence of friction and air resistance which absorbs the released energy when the first balloon pops up. But if the applied force is large enough to overcome these forces all balloons may pop up.
This question is very interesting and I liked it so much. Why can't you post this as a question. If you want assistance I will help you. If you agree I myself will post the problem. I have already framed the question and was now searching for the suitable picture.
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You can post it yourself.
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Thanks for the opportunity. I find the picture as soon as possible and will post the question.
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This and this.
I found some too.Log in to reply
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What is happening with the problem?
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I will post it tomorrow. I have got the pictures and constructed the question. Sorry for any delay.
I have posted it. You can check it here.