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@Rajdeep Dhingra
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Yes, this is due to the fact that log10(x) gives us the number of zeroes in the largest power of 10 which is less than x. For example, if x=12345, log10(x)=4(approx.) as 10000 is the largest power of ten below 12345. But we need to add one to this value to account for the leading number as we have now counted only the zeroes and left out the one in 10000. Therefore, the right answer is 4+1=5.
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Comments
⌊log10(2222)⌋+1= 1262612
The answer is log2222
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No, it is not, it is ⌊log10(2222)⌋+1
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I forgot to put it in Round function
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1. Floor function is understood.
You forgot to addLog in to reply
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n of a natural number x is given by:
I get the round off function bit. The thing that I meant is that the number of digitsn=⌊log10(x)⌋+1
n=⌊log10(x)⌋
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log10(x) gives us the number of zeroes in the largest power of 10 which is less than x. For example, if x=12345, log10(x)=4(approx.) as 10000 is the largest power of ten below 12345. But we need to add one to this value to account for the leading number as we have now counted only the zeroes and left out the one in 10000. Therefore, the right answer is 4+1=5.
Yes, this is due to the fact thatIn general: 10k has ⌊k⌋+1 digits.
22log2+1 = 7 (log2 =.3010)
Is there any way of calculation without using logarithms?
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yes, we could try writing it as 10 to a certain power(changing base/power.)
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