You have a cannon a distance before the start of a hill. The hill goes up at an angle from the ground. What angle and velocity must you shoot a cannon ball so that it lands a distance up the hill?(The distance s is measured from the bottom of the hill, i.e. the distance along the hill).
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2^{34}
a_{i-1}
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\sqrt{2}
\sum_{i=1}^3
\sin \theta
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I think there are infinite solutions to this problem. There are infinite parabolas passing through (0,0) and (d+sCosθ,sSinθ), the cannon at (0,0).
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Well, I believe that the gravitational field is fixed, so you may assume that acceleration is a....
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Niranjan sir is right since angle and velocity both are upto us there are infinite possibilities.One of them has to be given for a finite(2 if velocity is given[not always]) number of solutions.
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So, what is the relationship between θ and v?
I got v=(d+scosθ)2(sin2α)(d+scosθ)−ssinθcos2αg where v and α is the required velocity and angle. As you say , there are infinitely many solutions. Is this correct?
This question is given to me by @Josh Silverman Sir.
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The above equation has two unknowns. Only one equation. Thus infinity solutions.
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Hey guys, I've made this into a well-constrained problem, here