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Math
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2 \times 3
2×3
2^{34}
234
a_{i-1}
ai−1
\frac{2}{3}
32
\sqrt{2}
2
\sum_{i=1}^3
∑i=13
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Comments
There is no legitimate way to prove that 1=2. Do you know why? Because 1=2.
On one point in your "proof", you divided by zero. You can't do that. Mathematics won't take responsibility for anything that happens after you divide by zero.
You could have saved yourself the trouble by writing 1×0=2×0 and cancel out the zeros to get 1=2. But that is invalid. Any proof that allows division by zero isn't a proof at all.
1 squared=1
2 squared=2+2
3squared=3+3+3
in the same way
X squared= X+X+X+X+X+X+X+X+X+.......+X X times _{1}
differentiate both sides of 1 with respect to X
2X=1+1+1+1+1+1+1+1+1+.............+1 X times
i.e 2X=X
therefore 2=1
Notice that your definition of x2 is incomplete because it only works for positive integer values of x. Graph it and you'll get points, not a line. Your function is not continuous. You can't even differentiate it.
What does the operator dxd do? It takes a function f(x) and spits out a new function that tells you what the slope of f(x) is for a particular x.
If you want to find the slope of f(x) for a particular x graphically, what do you do?
You find the point (x,f(x)) and draw a straight line tangential to f(x) at that point. Then you calculate tanθ where θ is the angle our straight line makes with the positive x axis.
Now let's get back to your problem. Do you remember that we had points scattered on the xy plane? Let's find the slope of your defined function x2 for a particular x. Now how do we do that? Can you draw a line tangential to a point? Nope.
Moral: You can't differentiate discontinuous functions.
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
...\]
to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
There is no legitimate way to prove that 1=2. Do you know why? Because 1=2.
On one point in your "proof", you divided by zero. You can't do that. Mathematics won't take responsibility for anything that happens after you divide by zero.
You could have saved yourself the trouble by writing 1×0=2×0 and cancel out the zeros to get 1=2. But that is invalid. Any proof that allows division by zero isn't a proof at all.
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1 squared=1 2 squared=2+2 3squared=3+3+3 in the same way X squared= X+X+X+X+X+X+X+X+X+.......+X X times _{1} differentiate both sides of 1 with respect to X 2X=1+1+1+1+1+1+1+1+1+.............+1 X times i.e 2X=X therefore 2=1
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Notice that this argument is similar to this one.
So, what is wrong with your 'proof'?
Notice that your definition of x2 is incomplete because it only works for positive integer values of x. Graph it and you'll get points, not a line. Your function is not continuous. You can't even differentiate it.
What does the operator dxd do? It takes a function f(x) and spits out a new function that tells you what the slope of f(x) is for a particular x.
If you want to find the slope of f(x) for a particular x graphically, what do you do?
You find the point (x,f(x)) and draw a straight line tangential to f(x) at that point. Then you calculate tanθ where θ is the angle our straight line makes with the positive x axis.
Now let's get back to your problem. Do you remember that we had points scattered on the xy plane? Let's find the slope of your defined function x2 for a particular x. Now how do we do that? Can you draw a line tangential to a point? Nope.
Moral: You can't differentiate discontinuous functions.
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