Proof of 1=2

X=X Squaring X^2=X^2 Therefore X^2 -X ^2=0 (X+X)(X-X)=0 (By factorisation) Also X(X-X)=0 Or X+X=X 1=2

Note by R G
7 years, 10 months ago

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Comments

There is no legitimate way to prove that 1=21=2. Do you know why? Because 121\neq 2.

On one point in your "proof", you divided by zero. You can't do that. Mathematics won't take responsibility for anything that happens after you divide by zero.

You could have saved yourself the trouble by writing 1×0=2×01\times 0=2\times 0 and cancel out the zeros to get 1=21=2. But that is invalid. Any proof that allows division by zero isn't a proof at all.

Mursalin Habib - 7 years, 10 months ago

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1 squared=1 2 squared=2+2 3squared=3+3+3 in the same way X squared= X+X+X+X+X+X+X+X+X+.......+X X times _{1} differentiate both sides of 1 with respect to X 2X=1+1+1+1+1+1+1+1+1+.............+1 X times i.e 2X=X therefore 2=1

A Former Brilliant Member - 7 years, 10 months ago

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Notice that this argument is similar to this one.

So, what is wrong with your 'proof'?

Notice that your definition of x2x^2 is incomplete because it only works for positive integer values of xx. Graph it and you'll get points, not a line. Your function is not continuous. You can't even differentiate it.

What does the operator ddx\frac{d}{dx} do? It takes a function f(x)f(x) and spits out a new function that tells you what the slope of f(x)f(x) is for a particular xx.

If you want to find the slope of f(x)f(x) for a particular xx graphically, what do you do?

You find the point (x,f(x))(x, f(x)) and draw a straight line tangential to f(x)f(x) at that point. Then you calculate tanθ\tan \theta where θ\theta is the angle our straight line makes with the positive xx axis.

Now let's get back to your problem. Do you remember that we had points scattered on the xyxy plane? Let's find the slope of your defined function x2x^2 for a particular xx. Now how do we do that? Can you draw a line tangential to a point? Nope.

Moral: You can't differentiate discontinuous functions.

Mursalin Habib - 7 years, 10 months ago

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@Mursalin Habib yeah but y=x^2 is a continous problem

Abdhi Sharan - 6 years, 3 months ago
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