By Newton's Third Law of Motion,
\[\mathbf{F}_{12}=-\mathbf{F}_{21}\]
By Newton's Second Law of Motion,
F12p˙1∫t1t2p˙1dtΔp1Δ(mv1)m1Δ(v1)m1(v1−u1)m1v1−m1u1m1v1+m2v2∑pf=−F21=−p˙2=−∫t1t2p˙2dt=−Δp2=−Δ(m2v2)=−m2Δ(v2)=−m2(v2−u2)=m2u21−m2v2=m2u2+m1u1=∑pi■
#Mechanics
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Comments
What happens when there are 3 objects?
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Alright, let's give this a try:
Let's say we have a bunch of masses, in a system with only internal forces. where mass mi exerts a force on mj denoted by Fij. Thus, the net force is a sum of all the internal forces:
Fnet = i, j∑ Fij
By Newton's Third Law, we will have Fij = −Fji (if mi exterts Fij on mi, then it follows that mj exerts an equal an opposite force on mi. We also know that:
Fnet = dtdptotal
Thus, we can write our sum as a bunch of Fij + Fji = Fij − Fij = 0 terms, which just equates to 0, giving us:
Fnet = dtdptotal = 0
This implies that total momentum does not change with time, thus momentum is conserved when there are only internal forces acting on the system.
I probably missed a lot of nuances, how did I do @Josh Silverman? :)
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I think these aren't proves, but only a verification of the law for a particular case.
It looks like a nose.
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Yes really 😂 But good proof
lol