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It's not by induction, but an easy proof of Fermat's little theorem would be that xp≡(1+1+1+...+1)p≡(1p+1p+...+1p)≡x(modp) with x times number 1. This is possible because in Pascal's triangle on prime rows the numbers are multiples of p except for the first and last terms which are 1. This can be easily proven by using binomial formula.
Took some time to realize...
The actual answer is 1921.99999995586722540291132837029507293441170657370868230...
Unfortunately, most calculators round the answer.
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This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
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Are you looking for a simple proof of Fermat's Little Theorem or Fermat's Last Theorem or one of the many other theorems named after Fermat?
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FERMATS LAST THEOREM
I'm pretty sure Fermat's Last Theorem
Fermat's Little Theorem can be proved using induction.
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Can u prove it by induction plz show?
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It's not by induction, but an easy proof of Fermat's little theorem would be that xp≡(1+1+1+...+1)p≡(1p+1p+...+1p)≡x(modp) with x times number 1. This is possible because in Pascal's triangle on prime rows the numbers are multiples of p except for the first and last terms which are 1. This can be easily proven by using binomial formula.
Okay get your calculators and try this:
12178212+184112
=1922 right?
So this implies that 178212+184112=192212
Does this disprove Fermat's Last Theorem?
Of course not!
The calculator is wrong.
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BTW: A quick check to see that 178212+184112=192212 is to note that the left side is odd whereas the right side is even.
Took some time to realize... The actual answer is 1921.99999995586722540291132837029507293441170657370868230... Unfortunately, most calculators round the answer.
If I remember correctly, that "equation" was from a Homer Simpson episode.
I can give you a proof .