Proof of Trigonometric functions

Just have a look at the picture. You now don't need any $\pi$ there!!! I think that trigonometry came this way...

#NumberTheory #CosinesGroup #Cosines

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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

gud

Kushagra Sahni - 7 years, 3 months ago

thanks... I thought of deriving a precise value of $\pi$ to any number of digits, and not by using infinite series, so, with this success, i got to prove these trigonometric functions and calculate the value of many angles.

Fahad Shihab - 7 years, 3 months ago

These triangles already exist. They are called special triangles. If you want to calculate pi then just divide circumference with diameter. It's as easy as that.

William G. - 5 years, 8 months ago

@William G. – Yeah, you are right... Now part of textbooks... But in order to calculate pi, circumference must be known. No measurement can be precise to even 15 digits. So, these are a good method to find out those.

Fahad Shihab - 5 years, 7 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$