prove it!!!!!!!!!!!!!!!!(2)

Prove that a purely real number can never became equal to a purely imaginary number (Provided that the number is not 0+0i)

#Algebra #ComplexNumbers #Proofs #FindX #FindXandY

Easy Math Editor

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`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
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Comments

A pure imaginary number is of the form $bi$ where $b$ is a [non-zero] real number and $i^2=-1$ .

If $a$ real number were equal to $bi$ , then we would have $a^2=-b^2$ which is impossible since the right hand side is negative while the left hand side is non-negative.

Mursalin Habib - 6 years, 9 months ago

Thanks for replying you are awsome in proof problems

Aman Sharma - 6 years, 9 months ago

Thanks! But I wouldn't say I'm awesome.

Mursalin Habib - 6 years, 9 months ago

@Mursalin Habib – No, you realy are awsome, also your set ''proof problem of the day'' is realy cool one

Aman Sharma - 6 years, 9 months ago

Sorry, all real numbers are complex numbers. If this is from NCERT, exercise and problem number please?

Agnishom Chattopadhyay - 6 years, 9 months ago

Edited

Aman Sharma - 6 years, 9 months ago

Actually, by the definition of complex numbers, a real number is also considered a complex number. Think of it as like, we can write x as x + 0i.

Zi Song Yeoh - 6 years, 9 months ago

I am editing it thanks for pointing out the mistake

Aman Sharma - 6 years, 9 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$