prove it!!!!!!!!!!!!!!(4)

Prove that sagments joining the mid points of adjacent sides of a quadrilatral always form a parallelogram

#Geometry #Polygons #Quadrilaterals #Proofs #AnalyticalGeometry

Note by Aman Sharma
6 years, 8 months ago

No vote yet
1 vote

  Easy Math Editor

This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

When posting on Brilliant:

  • Use the emojis to react to an explanation, whether you're congratulating a job well done , or just really confused .
  • Ask specific questions about the challenge or the steps in somebody's explanation. Well-posed questions can add a lot to the discussion, but posting "I don't understand!" doesn't help anyone.
  • Try to contribute something new to the discussion, whether it is an extension, generalization or other idea related to the challenge.
  • Stay on topic — we're all here to learn more about math and science, not to hear about your favorite get-rich-quick scheme or current world events.

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 2×3 2 \times 3
2^{34} 234 2^{34}
a_{i-1} ai1 a_{i-1}
\frac{2}{3} 23 \frac{2}{3}
\sqrt{2} 2 \sqrt{2}
\sum_{i=1}^3 i=13 \sum_{i=1}^3
\sin \theta sinθ \sin \theta
\boxed{123} 123 \boxed{123}

Comments

Vector geometry is hardly ever used on Brilliant when, really, it should be used a whole lot more. Let's say that the four vertices of a quadrilateral are defined by vectors a,b,c,da,b,c,d. Then the the vectors between adjacent midpoints are

12(a+b)12(b+c)\dfrac { 1 }{ 2 } \left( a+b \right) -\dfrac { 1 }{ 2 } \left( b+c \right)
12(c+d)12(d+a)\dfrac { 1 }{ 2 } \left( c+d \right) -\dfrac { 1 }{ 2 } \left( d+a \right)

that is

12(ac)\dfrac { 1 }{ 2 } (a-c)
12(ca)\dfrac { 1 }{ 2 } (c-a)

which means they're parallel. Do same for the other set.

Michael Mendrin - 6 years, 8 months ago

Log in to reply

Sir is there any way to prove it by euclid's geometry

Aman Sharma - 6 years, 8 months ago

Log in to reply

Well, draw a diagonal from opposite corners of the quadrilateral. That forms 2)2) triangles. Then it's easy to prove that the diagonal is parallel to the line through the midpoints of the sides of each of the 22 triangles. Hence, they're both parallel. Do the same for the other set. This is really the same thing as with the vector proof, but can be implemented using Euclid's geometry.

Michael Mendrin - 6 years, 8 months ago
×

Problem Loading...

Note Loading...

Set Loading...