Proving that lines are parallel

Hi, I need help solving this problem - any help would be appreciated :)

$P$ and $Q$ are points on the bisector of the exterior angle $A$ of triangle $ABC$ with A between $P$ and $Q$, and $PB$ is parallel to $QC$. Point $D$ is on BC such that $DP=DQ$. Prove that $AB$ is parallel to $DQ$.

#Geometry

Easy Math Editor

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Comments

I have drawn a sketch for the problem , but according to your statements DQ is part of PQ,which passes through point A. so far, as DQ & AB , both of them passes through point A , that means , they intersect at point A . therefore they can not be parllel. because they intersect.

Aziz Alasha - 4 years, 1 month ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$