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In the theory of learning in psychology, probabilities t and p and a constant b are related by: t = (1-b)p

Show that this equation may be written as: 1-t = (1-b)(1-p) + b

How?

#Algebra

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Comments

$1 -t = 1-(1-b)p$

$=1-(1-b)\left(1-(1-p)\right)$

$=1-(1-b)+(1-b)(1-p)=b+(1-b)(1-p)$

Hence, proved.

Janardhanan Sivaramakrishnan - 5 years, 10 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$