Draw 2 parallel lines, the lengths of which correspond to 2 numbers A and B whose average you wish to find.
Connect the endpoints of these lines so as to form a trapezoid/trapezium.
Bisect each of the legs of this trapezoid/trapezium and connect their midpoints. (This line is called the median)
The length of this line is the average of the two numbers A and B.
Though relatively simple, I thought it was so cool how a mathematical concept like average could be represented completely geometrically, without any knowledge of math!
Anybody want to take a stab at proving that the median is indeed the average of the 2 lines?
Easy Math Editor
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Comments
Visually if you just cut by the red line the trspezium take upper region rotate 180 degrees and glue the two part putting base B with base A. You will obtain a parallelogram one side measure A+B and the other 2m therefore m=(A+B)/2. Old people figured out this way
Suppose ABDC is a trapezium, so that the vectors a=AB and b=CD are parallel. So, let a=λv and b=μv, for some vector v. Also suppose that c=AC and d=DB. Let M,N be the respective midpoints of AC and BD; this means that AM=MC=21c and NB=DN=21d.
So, we have that
MN=21(c+d)+μv=−21(c+d)+λv.
Hence,
2MN=(λ+μ)v
and as a result
MN=2λ+μv.
We understand the quantity 2λ+μ to be the arithmetical mean of λ and μ, so we have to understand that the line segment connecting the midpoints of the non-parallel sides of a trapezium is half the "sum" of the line segments of the parallel sides of a trapezium; note the lack of use of "lengths" in not only the proof, but also the result obtained.
P.S. The origins of our understanding of mathematics are purely geometric (aside from the idea of counting objects); the Greeks had the right idea in thinking geometrically, and it has carried on until the turn of the last century, when mathematics started to go deeply south.