Main post link -> http://purplecomet.org/home/resource/347/HIGHSCHOOLPROBLEMS.pdf
Problem: Points A and B are the endpoints of a diameter of a circle with center C. Points D and E lie on the same diameter so that C bisects segment DE. Let F be a randomly chosen point within the circle. The probability that triangle DEF has a perimeter less than the length of the diameter of the circle is 17/128. There are relatively prime positive integers m and n so that the ratio of DE to AB is m/n . Find m + n.
I approached this problem by spitting the circle in two halves with diameter AB and then again halving the circle by drawing a perpendicular XC to AB. Now the problem becomes finding CE/CB given that the probability that XB<CB is 17/128. I can't work out the solution from here..
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
...\]
to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
There are no comments in this discussion.