Question of arrangement....

36 identical chairs must be arranged in rows with the same number of chairs in each row. Each row must contain at least three chairs and there must be at least three rows. A row is parallel to the front of the room. How many different arrangements are possible?

not able to solve........please give solutions.... :|

#MathProblem

Easy Math Editor

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`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
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`\boxed{123}`	$\boxed{123}$

Comments

12x3 , 3x12 , 6x6 , 4x9 , 9x4 - 5 arrangements possible. Hope it's not a brilliant problem.

Bhargav Das - 8 years, 1 month ago

@bhargav- buddy i thought the same....but the answer is 3 and i dnt knw how?////

A Former Brilliant Member - 8 years, 1 month ago

the answer is definitely 5 arrangements....maybe the answer in the book is wrong,..

mohammed khan - 8 years, 1 month ago

@Mohammed Khan – ya...maybe....b/w thanks Mohammed and Bhargav...

A Former Brilliant Member - 8 years, 1 month ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$