Question on circular motion

how do we find the theta in this picture?

the course stated that theta= 2 pi

how do you get there? can anyone explain... it would be a big help :)

#Mechanics

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Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
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Comments

We needed $\theta$ for the calculation of angular velocity $\omega$ . Angular velocity in a circular motion with uniform speed is defined as the ratio of the angle rotated $\theta$ to the time taken to rotate.

For one complete rotation (That is the axe is rotated in a complete circle) the angle rotated is $2 \pi \text{ rad}$ .

Rohit Gupta - 3 years, 4 months ago

Thanks !

darren vincent - 3 years, 4 months ago

Most welcome.

Rohit Gupta - 3 years, 4 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$