Rant

Three cylinders, all of the same mass, are stacked on a table as shown in the figure. There is enough friction between the cylinders and the table such that the cylinders remain at rest. Let Fh be the horizontal force of the table on one of the cylinders and Fn be the normal force. When Fh is a minimum, what is the ratio Fh/Fn?

How is the answer not sqrt(3)/8 or sqrt(3)/24? I demand to be put in level 5 mechanics. There is something wrong with this question. I know I am not supposed to discuss problem answers, but I don't care.

Easy Math Editor

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`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
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Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$