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Open the link given above and see the question mark. Please fill in the question mark. There is a pattern either row wise or column wise. If someone wants the options, they are posted below: (A)14 (B)15 (C)16 (D)17
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As stated, this is not a magic square. But assuming it's one of those "brain "teaser" tests", here's a solution that I see perfectly valid while not helping you at all:
The third number in each row is the minimum of the other two numbers in the row, multiplied by their sum.
By this, the question mark is either 64 or 2−1−329. Neither is among the given choices.
The above simply states that doing such questions just wastes your time, because there are infinitely many interpretations possible, and a bunch of "plausible" interpretations.
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Thank you Ivan for correcting me! The same question appeared in an examination which I gave. Can you come up with a solution among the four options?
This is not a magic square ! The sum of the numbers in each column and row must be same in a Magic square
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Thank You for correcting my knowledge about the magic squares. Well, did you come up with any more answers?
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The answer is 14.
8+2+10=20
4+6+30=40
x+1+50=65
we end up x=14
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Well guys, I think Rashmi gave the most accurate answer of this problem. Thanks a lot Rashmi. Nice try Ivan, Bhargav and Likhita!
i got 64 without the the options
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In the examination, the options enlisted were only these. I am sure the answer is one of the above options which I gave. Thank You for giving an answer. Can you provide a solution also?
I think the logic used here ,to get one of the options given as the answer is: 20−(8×2)=4=22 40−(4×6)=16=42. That is, the above pattern is followed to get a perfect square. So,putting the various values we get,16 as our required answer as 65−(1×16)=49=72, which is a perfect square. Hope that helps!
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I tried this logic of yours many a times but I don't think it is the most accurate answer. Nonetheless, nice try Bhargav. I think Rashmi gave the most accurate answer. Go check hers!
Please I want the answer asap. If possible please provide me the solution.