Calculate resistance of a wire if the following are given -
\(Mass\) = \(50 g\)
ResistivityResistivityResistivity = 1.8∗10−9ohm−metre1.8 * 10^{-9} ohm-metre1.8∗10−9ohm−metre
LengthLengthLength = 5m 5 m5m
DensityDensityDensity = 1.8∗106kg/m21.8 * 10^{6} kg/m^{2}1.8∗106kg/m2
Note by Sahba Hasan 5 years, 9 months ago
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2^{34}
a_{i-1}
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Mass=volume×density. Volume=area×length. Resistance=resistivity×length÷area Resistance=resistivity ×length×length÷volume
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Can you provide more detailed steps along with the answer? i tried the same method.
5*10^{-15}
R=ρ⋅LAR=\rho\cdot \dfrac{L}{A}R=ρ⋅AL
We only need to find AAA. For that, first figure out what the volume is (using density and mass) and then divide it by L to get AAA.
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Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
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to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
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Mass=volume×density. Volume=area×length. Resistance=resistivity×length÷area Resistance=resistivity ×length×length÷volume
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Can you provide more detailed steps along with the answer? i tried the same method.
5*10^{-15}
R=ρ⋅AL
We only need to find A. For that, first figure out what the volume is (using density and mass) and then divide it by L to get A.