Resultant force question

Which of the following pair of forces can give a resultant force 2 N?

A) 1 N and 2 N

b) 1 N and 5 N

C) 2 N and 5 N

D) 1 N and 4 N

can anyone please explain the solution?

#Mechanics

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Comments

None:

$4N - N = 3N$

$5N - 2N = 3N$

$5N - N = 4N$

$2N - N = N$

Note: $N = 1N$

Yajat Shamji - 10 months, 3 weeks ago

Thanks, my textbook probably had a typo.

shruthi srinivasan - 10 months, 3 weeks ago

No problem!

Yajat Shamji - 10 months, 3 weeks ago

@Yajat Shamji, I don't understand, how do you know that the forces are acting opposite to each other? Why are you directly subtracting them?

Vinayak Srivastava - 10 months, 2 weeks ago

Well, generally "pairs" of forces refers to forces acting in opposite direction to each other.

Krishna Karthik - 10 months, 1 week ago

I think the angle b/w the forces should be mentioned.

Vinayak Srivastava - 10 months, 3 weeks ago

I agree. You can modify the angle of the forces to create a resultant force vector with magnitude $2N$ .

Krishna Karthik - 10 months, 1 week ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$