RMO 2016 practice board

Hello everyone!

As many of us are preparing for RMO (Regional Mathematics Olympiad), let us start posting problems and help each other prepare. Everyone is more than welcome to post problems or post the solutions to problems.

Here is a problem to start with:

In ΔABC\Delta ABC, OO is the circumcenter and HH is the orthocenter. If AO=AHAO=AH, prove that A=60\angle A=60^\circ.

Also, if the circumcircle of ΔBOC\Delta BOC passes through H, prove that A=60\angle A=60^\circ.

#Geometry

Note by A Former Brilliant Member
4 years, 8 months ago

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1 vote

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Solution

1)Extend BO to meet at the circumcircle of the ∆ at M.Also extend CH to meet at AB at N and AH meet BC at K.Join AM and MC.

Now observe that angle ANC = angle BAM = 90°.This implies AM || CN.

Similarly,AH || CM.

This implies,AHMC is a parallelogram.

Now, AH = MC(=OA because AH=AO.)

Thus,OMC is an equilateral triangle with angle MOC =60°.

angle BOC = 180° - angle MOC = 120°.

This implies angle BAC = 60°

Harsh Shrivastava - 4 years, 8 months ago

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I can't edit my comment, its "AHCM".

Harsh Shrivastava - 4 years, 8 months ago

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Brilliant staff are working on this issue.

Sharky Kesa - 4 years, 8 months ago

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@Sharky Kesa Hey Sharky post some problems (RMO level.)

Harsh Shrivastava - 4 years, 8 months ago

can u post the solution for the 2nd part of problem 1

A Former Brilliant Member - 4 years, 8 months ago

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I will try to solve it and if I succeed ,I'll post the solution.

Harsh Shrivastava - 4 years, 8 months ago

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@Harsh Shrivastava i got it here is the solution [url=https://postimg.org/image/e0cnnt8w5/][img]https://s18.postimg.org/e0cnnt8w5/IMG_0100.jpg[/img][/url]

A Former Brilliant Member - 4 years, 8 months ago

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@A Former Brilliant Member sorry https://postimg.org/image/ylrffpqh1/ https://postimg.org/image/e0cnnt8w5/ open the links

A Former Brilliant Member - 4 years, 8 months ago

@Harsh Shrivastava the 1 st part can be solved much much easily AO=AH R=2RcosA 2cosA=1 cosA=1/2 A=60 done!!

A Former Brilliant Member - 4 years, 8 months ago

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@A Former Brilliant Member Oh that's awesome use of trignometery!

Harsh Shrivastava - 4 years, 8 months ago

@A Former Brilliant Member See an even more efficient use of trigonometrytrigonometry. 1st Part of @Svatejas Shivakumar 's question :

1.1. Draw ODBCOD\perp BC.

AOAO = AHAH => BOBO = 2OD2OD => cos\cos BOD\angle BOD = 1/21/2 => BOD\angle BOD = 6060 => BOC\angle BOC = 120120 => A\angle A = 6060.

Second part :

22 Quad. BHOCBHOC is cyclic.

=> BHC\angle BHC = BOC\angle BOC

=> 180A180 - \angle A = 2A2 \angle A

=> A\angle A = 180/3180 / 3 = 6060.
I know, as expected it was a nontrigonometricnon-trigonometric one.

Vishwash Kumar ΓΞΩ - 4 years, 2 months ago

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@Vishwash Kumar Γξω please explain how BO = 2 OD if AO = AH. Thanks!

Yash Mehan - 3 years, 12 months ago

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@Yash Mehan That's just one of the Euler line properties. In a triangle ΔABC\Delta ABC, if OO is the circumcenter, HH is the orthocentre and DD is the foot of perpendicular from OO on BCBC then by a well known result AH=2ODAH = 2OD.

Vishwash Kumar ΓΞΩ - 3 years, 12 months ago

In a triangle ABCABC the point DD is the intersection of the interior angle bisector of BAC\angle BAC with side BCBC. The line through AA that is perpendicular to ADAD intersects the circumcircle of triangle ABCABC for a second time at point PP. A circle through points AA and PP intersects line segment BPBP internally in EE and line segment CPCP internally in FF.

Prove DEP=PFD\angle DEP = \angle PFD.

Sharky Kesa - 4 years, 8 months ago

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I have seen this question earlier in one of my books.

Its a good problem. As i have solution of it, i will not post this now. Let others try also.

Priyanshu Mishra - 4 years, 8 months ago

Vishwash Kumar ΓΞΩ - 4 years, 2 months ago

Below is the diagramdiagram.

Const:Const: Let APE\odot APE be the circle passing through AA and P.P.[where EE is a point on BPBP.] Join AEAE, AF.AF.

SolutionSolution: Let BAD\angle BAD = CAD\angle CAD = θ\theta.

Then PAC\angle PAC = PBC\angle PBC = PCB\angle PCB = 9090 - θ\theta & BPC\angle BPC = EPF\angle EPF = EAF\angle EAF = 2θ.2\theta.

Now, BAC\angle BAC = EAF\angle EAF => BAE\angle BAE = CAF\angle CAF. Also, ABE\angle ABE = ACF\angle ACF

=> ΔABEΔACF\Delta ABE\sim \Delta ACF => ABAC\dfrac{AB}{AC} = BECF\dfrac{BE}{CF} ( Similarity properties )

Now, EBD\angle EBD = FCD\angle FCD = 9090 - θ\theta , BECF\dfrac{BE}{CF} = ABAC\dfrac{AB}{AC}. But also BDCD\dfrac{BD}{CD} = ABAC\dfrac{AB}{AC} => BECF\dfrac{BE}{CF} = BDCD\dfrac{BD}{CD}.

=> ΔEBDΔFCD\Delta EBD\sim \Delta FCD.

=> BED\angle BED = CFD\angle CFD =>DEP=PFD\angle DEP = \angle PFD.

KIPKIG.KIPKIG.

Vishwash Kumar ΓΞΩ - 4 years, 2 months ago

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How do you draw diagrams on the computer? Is there some tool you use?

Yash Mehan - 3 years, 12 months ago

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@Yash Mehan yes ..like geogebra

Ayush G Rai - 3 years, 12 months ago

Well, this first part of the question can't be right! (Below is a summary of why)

If AO=OHAO=OH, HH must also be on the circumcircle of ABCABC, from which we get the triangle being right-angled, and HH is on the vertex with right angle. Nothing else can be gathered from the given information.

Perhaps you meant AO=AHAO=AH, which makes sense.

Sharky Kesa - 4 years, 8 months ago

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Yes you are right. Thanks for pointing it out.

A Former Brilliant Member - 4 years, 8 months ago

In ΔABC\Delta ABC, O is the circumcenter and H is the orthocenter. Prove that AH2+BC2=4AO2AH^2+BC^2=4AO^2.

A Former Brilliant Member - 4 years, 8 months ago

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Draw ODBCOD\perp BC.

Just PythagorasPythagoras then, BD2BD^{2} ++ OD2OD^{2} = BO2BO^{2}

=> 44 BD2BD^{2} ++ 44 OD2OD^{2} = 44 BO2BO^{2}

=> [2BD]2[2BD]^{2} ++ [2OD]2[2OD]^{2} = 44 BO2BO^{2}

=> BC2BC^{2} + AH2AH^{2} = 44 AO2AO^{2}.

Vishwash Kumar ΓΞΩ - 4 years, 2 months ago

Can you post the solution please ?

Alan Joel - 4 years, 8 months ago

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i got it , its easy https://postimg.org/image/5d1sm6hm7/

A Former Brilliant Member - 4 years, 8 months ago

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@A Former Brilliant Member How did you get AH^2 = 2RcosA ?

Alan Joel - 4 years, 8 months ago

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@Alan Joel Its an identity.

Priyanshu Mishra - 4 years, 8 months ago

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@Priyanshu Mishra Its AH*

Alan Joel - 4 years, 8 months ago

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@Alan Joel Oh, I knew that but I forgot lol

Alan Joel - 4 years, 8 months ago

Here's the link to last year's RMO board

Harsh Shrivastava - 4 years, 8 months ago

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Thanks. But I left Olympiad mathematics forever.

Swapnil Das - 4 years, 8 months ago

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WHATT!!!!!!!!!!!!!

Harsh Shrivastava - 4 years, 8 months ago

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@Harsh Shrivastava That's true.

Swapnil Das - 4 years, 8 months ago

Are you ok? Say no

Nihar Mahajan - 4 years, 8 months ago

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@Nihar Mahajan Yes, I'm fine.

Number Theory, Euclidean Geometry, Classical Inequalities...

Do they have any important application in my life? No, never. On the other hand, what I learn for the physics Olympiads will certainly have a huge impact on my future. Moreover, MOs make me slow, which is very harmful for these upcoming 3 years of my life. I'll be learning Math of relevant context like Calculus and stuff for PhOs, which will keep me away from MOs as well as keep my interest for math always alive.

Swapnil Das - 4 years, 8 months ago

Sorry guys, I wasn't active on brilliant (and might not be for a period of time) Best luck for your rmos

Nihar Mahajan - 4 years, 8 months ago

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Actually RMO happened today for most of the regions. Some are on 16th.

A Former Brilliant Member - 4 years, 8 months ago

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@A Former Brilliant Member yep, i gave it today :)

Nihar Mahajan - 4 years, 8 months ago

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@Nihar Mahajan How was it?

A Former Brilliant Member - 4 years, 8 months ago

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@A Former Brilliant Member pretty good, better than last time's

Nihar Mahajan - 4 years, 8 months ago

@A Former Brilliant Member How was ur rmo?how many did get correct?

naitik sanghavi - 4 years, 8 months ago

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@Naitik Sanghavi Mine is on 16th. How was your paper?

A Former Brilliant Member - 4 years, 8 months ago

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@A Former Brilliant Member 3-4 correct ,This time 2 question were very easy, so may be cutoff will go high!

naitik sanghavi - 4 years, 8 months ago

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@Naitik Sanghavi From which region did u give RMO?

rajdeep das - 4 years, 8 months ago

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@Rajdeep Das Gujarat

naitik sanghavi - 4 years, 8 months ago

@Naitik Sanghavi Please most the paper.

Harsh Shrivastava - 4 years, 8 months ago

@Nihar Mahajan Please most the paper.

Harsh Shrivastava - 4 years, 8 months ago

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@Harsh Shrivastava How to most a paper? 😂😂 XD

Nihar Mahajan - 4 years, 8 months ago

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@Nihar Mahajan Lol I meant post.Please post your paper.

Harsh Shrivastava - 4 years, 8 months ago

What is circumdiameter?

Harsh Shrivastava - 4 years, 8 months ago

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sorry it is circumcenter.

A Former Brilliant Member - 4 years, 8 months ago

I am also giving the RMO this year, please help me out 😀

Alan Joel - 4 years, 8 months ago

Prove that a2+b2+c2d2>13\dfrac{a^2+b^2+c^2}{d^2} >\dfrac{1}{3} , where a,b,c,d are the sides of a quadrilateral.

Harsh Shrivastava - 4 years, 8 months ago

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This question I have done before (I'm pretty sure it was an application of QM-AM), so I'm leaving it as an exercise for everyone else.

Sharky Kesa - 4 years, 8 months ago

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I have a solution using trivial inequalities.

Harsh Shrivastava - 4 years, 8 months ago

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@Harsh Shrivastava QM-AM is trivial.

Sharky Kesa - 4 years, 8 months ago

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@Sharky Kesa Yes after QM-AM the result directly follows.

A Former Brilliant Member - 4 years, 8 months ago

@Sharky Kesa Alright.Post some problems.

Harsh Shrivastava - 4 years, 8 months ago

3) Let kk be an integer and let

n=k+k213+kk213+1n=\sqrt[3]{k+\sqrt{k^2-1}} + \sqrt[3]{k-\sqrt{k^2-1}}+1

Prove n33n2n^3 - 3n^2 is an integer.

Sharky Kesa - 4 years, 8 months ago

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Hint : Use the fact that if a+b+c = 0 then a3+b3+c3=3abca^3+b^3+c^3 = 3abc

Harsh Shrivastava - 4 years, 8 months ago

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Good choice from MATHEMATICAL OLYMPIAD TREASURES.

Priyanshu Mishra - 4 years, 8 months ago

(n1)3=(k+k213+kk213)3n33n2=2k21(n-1)^3=(\sqrt[3]{k+\sqrt{k^2-1}} + \sqrt[3]{k-\sqrt{k^2-1}})^3 \\ n^3-3n^2=2k-21

As kk is integer 2k22k-2 will also be an integer.

Akshat Sharda - 4 years, 8 months ago

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Firstly, your final statement is incorrect. Secondly, you have put no working. Sorry, but this is a null solution.

Sharky Kesa - 4 years, 8 months ago

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@Sharky Kesa Sorry but this is not a REGIONAL MATHEMATICAL OLYMPIAD level problem.

Please post difficult ones.

Priyanshu Mishra - 4 years, 8 months ago

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@Priyanshu Mishra OK, sorry! I'll post IMO level probs next time.

Sharky Kesa - 4 years, 8 months ago

Good but take nn on RHS and see that a+b+c=0a + b + c = 0, so a3+b3+c3=3abca^3 + b^3 + c^3 = 3abc and we are done.

Priyanshu Mishra - 4 years, 8 months ago

@Everyone

Find the smallest positive number λ\lambda, such that for any complex numbers z1,z2,z3{zCz<1}{z_1},{z_2},{z_3} \in \{z\in \mathbb C \big| |z| < 1\}, if z1+z2+z3=0z_1+z_2+z_3 = 0, then z1z2+z2z3+z3z12+z1z2z32<λ \left|z_1z_2 +z_2z_3+z_3z_1\right|^2+\left|z_1z_2z_3\right|^2 < \lambda.

Solve this and provide the solution.

Priyanshu Mishra - 4 years, 8 months ago

Determine all positive triplets of integers such that

 (x+1)y+1+1=(x+2)z+1.\large\ {(x+1)}^{y+1} + 1 = {(x+2)}^{z+1}.

Priyanshu Mishra - 4 years, 8 months ago

 3x3+5x5+17x17+19x19=x211x4\large\ \frac{3}{x-3}+\frac{5}{x-5}+\frac{17}{x-17}+\frac{19}{x-19}=x^2-11x-4.

Find the largest real solution to this equation.

Priyanshu Mishra - 4 years, 8 months ago

Suppose that k,n1,,nkk, n_1, \ldots, n_k are variable positive integers satisfying k3k \geq 3, n1n2nk1n_1 \geq n_2 \geq \ldots \geq n_k \geq 1, and n1+n2++nk=2016n_1 + n_2 + \ldots + n_k = 2016.

Find the maximal value of

i=1k2+1(ni2+1).\displaystyle \sum_{i=1}^{\left \lfloor \frac{k}{2} \right \rfloor + 1} \left ( \left \lfloor \dfrac {n_i}{2} \right \rfloor + 1 \right ) .

Sharky Kesa - 4 years, 8 months ago

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Please post again as you cannot edit that.

Priyanshu Mishra - 4 years, 8 months ago

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Sure I can! Mod powers! :P

Sharky Kesa - 4 years, 8 months ago

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@Sharky Kesa But how you edited that?

Priyanshu Mishra - 4 years, 8 months ago

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@Priyanshu Mishra With great skill (and a large screen)!

Sharky Kesa - 4 years, 8 months ago

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@Sharky Kesa What is that skill!?

Priyanshu Mishra - 4 years, 8 months ago

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@Priyanshu Mishra Big iMac skills! :P :P

Sharky Kesa - 4 years, 8 months ago

Best of luck everyone

rajdeep das - 4 years, 8 months ago

Did anyone give RMO from north zone?

rajdeep das - 4 years, 8 months ago

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Uttar Pradesh - Me

Rishik Jain - 4 years, 8 months ago

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At which center?

rajdeep das - 4 years, 8 months ago

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@Rajdeep Das Meerut

Rishik Jain - 4 years, 8 months ago

Mumbai region paper was really easy

Racchit Jain - 4 years, 8 months ago

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Could you post the question paper please?

Kush Singhal - 4 years, 8 months ago

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Yeah sure, but I use the app and I don't know how to post an image here, can you give me your email and I'll mail it to you?

Racchit Jain - 4 years, 8 months ago

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@Racchit Jain Post it on Slack.

Sharky Kesa - 4 years, 8 months ago

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@Sharky Kesa Umm...how do I do that?

Racchit Jain - 4 years, 8 months ago

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@Racchit Jain It's asking me too get the app can't I do it using the browser only?

Racchit Jain - 4 years, 8 months ago

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@Racchit Jain You can do it on the browser.

Sharky Kesa - 4 years, 8 months ago

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@Sharky Kesa Can I mail it to you and then you can post it?

Racchit Jain - 4 years, 8 months ago

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@Racchit Jain Sure. [email protected]

Sharky Kesa - 4 years, 8 months ago

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@Sharky Kesa I have sent it to you plz check

Racchit Jain - 4 years, 8 months ago

@Sharky Kesa Please post the paper.

Harsh Shrivastava - 4 years, 8 months ago

Can someone post this year's problems?

Sharky Kesa - 4 years, 8 months ago

Please someone post this years rmo question paper.

Harsh Shrivastava - 4 years, 8 months ago

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The papers are uploaded on AoPS.

A Former Brilliant Member - 4 years, 8 months ago

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Please give me the link.Thanks.

Harsh Shrivastava - 4 years, 8 months ago

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@Harsh Shrivastava I have posted Gujarat rmo paper here,https://brilliant.org/discussions/thread/rmo-2016-gujarat-region/?ref_id=1272714

naitik sanghavi - 4 years, 8 months ago

Given are two circles w1, w2 which intersect at points X, Y . Let P be an arbitrary point on w1. Suppose that the lines PX, PY meet w2 again at points A,B respectively. Prove that the circumcircles of all triangles PAB have the same radius.

Sayantan Saha - 4 years, 8 months ago

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this is north zone's (Delhi) problem

Sayantan Saha - 4 years, 8 months ago

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could u do it?

rajdeep das - 4 years, 8 months ago

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@Rajdeep Das Then pls post the solution

rajdeep das - 4 years, 8 months ago

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@Rajdeep Das Show that AB is independent of the choice of point P

Racchit Jain - 4 years, 8 months ago

@Rajdeep Das Try using sine rule

Racchit Jain - 4 years, 8 months ago

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@Racchit Jain It looks like Power of a Point, but Extended Sine Rule definitely works.

Sharky Kesa - 4 years, 8 months ago

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@Sharky Kesa please add the solution

Sayantan Saha - 4 years, 8 months ago

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@Sayantan Saha I won't give solution but the crux of this proof is to show that ABAB is constant, irrespective of where PP is.

Sharky Kesa - 4 years, 8 months ago

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@Sharky Kesa yeah. I have done it

Sayantan Saha - 4 years, 8 months ago

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@Sayantan Saha Two circles C1 and C2 intersect each other at points A and B. Their external common tangent (closer to B) touches C1 at P and C2 at Q. Let C be the reflection of B in line PQ. Prove that angleCAP = angleBAQ. Can you convince me what this reflection does mean.

Sayantan Saha - 4 years, 8 months ago

Hey!! Did anyone give GMO? Or RMO on 16th October. If yes please tell how many were you able to do, and what should be the expected cutoff

Racchit Jain - 4 years, 7 months ago

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What is your score in RMO?

Sayantan Saha - 4 years, 7 months ago

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I gave GMO

Racchit Jain - 4 years, 7 months ago

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@Racchit Jain However, I know marks of some of my friends from different regions, which region are you asking for?

Racchit Jain - 4 years, 7 months ago

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@Racchit Jain I am from WB region. I want to know how high the scores of rmo had gone in Delhi this year.

Sayantan Saha - 4 years, 7 months ago

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@Sayantan Saha The highest marks in Delhi that I know of is 35 out of 60 otherwise everyone is getting less than 15. The cutoff should be around 20 I think, but not more than 25

Racchit Jain - 4 years, 7 months ago

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@Racchit Jain Only 35. I don't think so.

At which website is the result of RMO declared?

Priyanshu Mishra - 4 years, 7 months ago

@Racchit Jain Pls give for delhi region also.

rajdeep das - 4 years, 7 months ago

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@Rajdeep Das Is RMO DELHI result out?

Priyanshu Mishra - 4 years, 7 months ago

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@Priyanshu Mishra Yes

rajdeep das - 4 years, 7 months ago

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@Rajdeep Das At which website?

Priyanshu Mishra - 4 years, 7 months ago

Use trigonometry as there is a right triangle formed assuming centet

Biswajit Barik - 4 years, 6 months ago

Hello everybody,

RMO results are out.

Who are selected?

Priyanshu Mishra - 4 years, 6 months ago

@Svatejas Shivakumar, @Harsh Shrivastava, @Ayush Pattnayak @Alan Joel @Racchit Jain @rajdeep das @naitik sanghavi and all other RMO aspirants ,I invite you'll to my RMO,INMO team. Those who are interested can give their email id over here.

Ayush G Rai - 4 years, 4 months ago

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I'm in, here's my email id [email protected]

Alan Joel - 4 years, 4 months ago

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I meant icloud* there

Alan Joel - 4 years, 4 months ago

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@Alan Joel you can check ur mail now

Ayush G Rai - 4 years, 4 months ago

Mine is [email protected]

rajdeep das - 4 years, 4 months ago

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Ok i have sent you an invite You can check your email

By the way I am the co owner of the team and ayush is the owner

A Former Brilliant Member - 4 years, 4 months ago

Me [email protected]

Ayush Pattnayak - 4 years, 3 months ago

Me too.... [email protected]

A Former Brilliant Member - 3 years, 8 months ago

All INMO participants,please share ur marks.

Ayush Pattnayak - 4 years, 4 months ago

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do u want to join my INMO team?

Ayush G Rai - 4 years, 4 months ago

70-80.

Priyanshu Mishra - 4 years, 4 months ago

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why dont u be active in slack?

Ayush G Rai - 4 years, 4 months ago

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@Ayush G Rai I don't have time for these "SLACK" things.

I have a lot of stuffs for FIITJEE. I do that only.

Priyanshu Mishra - 4 years, 4 months ago

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@Priyanshu Mishra oh...ok I am very sorry for disturbing u.

Ayush G Rai - 4 years, 4 months ago

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@Ayush G Rai Its true. Kuch mazaa nahi aata slack chat pe.

Priyanshu Mishra - 4 years, 4 months ago

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@Priyanshu Mishra Its not chatting.I invited bcoz ur an INMO qualifier and u can help us solve problems that are posted.

Ayush G Rai - 4 years, 4 months ago

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@Ayush G Rai Initially i am only RMO qualifier. I am not INMO qualifier till the result is declared.

Priyanshu Mishra - 4 years, 4 months ago

@Priyanshu Mishra Which centre?

rajdeep das - 4 years, 4 months ago

@Swapnil Das @Harsh Shrivastava @Ayush Pattnayak Please Help! I am a class 9 student and am Appearing for RMO. I am pretty intimidated by Geometry Problems.... I can make an accurate figure but I don't know how to proceed.(For example: This question by Brilliant Member) Please guide me on how to solve Geometry and geometrical proofs...... I know Theorems(like Menelaus' Ptolemy's, Sine rule, Co-sine rule) If I make it in INMO... You all will deserve the credit. Urgent Help Required!!

A Former Brilliant Member - 3 years, 8 months ago

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u just need some angle chasing and similarity for RMO.

Ayush G Rai - 3 years, 8 months ago

Just read those theorems and get into actual problem solving, you may also try British mathematical Olympiad problems, they are also RMO level. No sort of 'magical' construction required for RMO. Best of luck!

Harsh Shrivastava - 3 years, 8 months ago

RMO is over now. So no need to look at that. Now we should prepare for INMO.

I have posted a sample of 6 questions here. You can practice that and post more questions there also.

https://brilliant.org/discussions/thread/inmo-2017-board/.

Priyanshu Mishra - 4 years, 8 months ago

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It is not over in many regions, mine is on 16th.

Harsh Shrivastava - 4 years, 8 months ago

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Even mine is on 16th

Alan Joel - 4 years, 8 months ago

So wait upto that and then solve INMO problems.

Priyanshu Mishra - 4 years, 8 months ago

How was your rmo :)?

Nihar Mahajan - 4 years, 7 months ago

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@Nihar Mahajan Well it could not have been any more bad.

Very very bad. :(

Can do only one question, I succumbed to exam pressure :(

Though I could solve 3 out of remaining 5 question at home myself.

I know this this is a lame excuse but 😭

My Olympiad maths is officially over.

Sorry for long reply, wbu?

Harsh Shrivastava - 4 years, 7 months ago

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@Harsh Shrivastava Wth! Was the paper reallyl that tough? I solved 4 completely. I am on the boundary line of getting selected, since it's very difficult to get selected from my state, lot of competition here! 😅

Now it's ok, Harsh, I know you are gonna rock in other exams 😀😀

Nihar Mahajan - 4 years, 7 months ago

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@Nihar Mahajan Not sure about that rocking part :(

Harsh Shrivastava - 4 years, 7 months ago

@Nihar Mahajan Did you give from Mumbai region?

Racchit Jain - 4 years, 7 months ago

@Harsh Shrivastava Your Olympiad maths journey is not over. Congo :)

Nihar Mahajan - 4 years, 6 months ago

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@Nihar Mahajan It might have been over if i was in a state like yours.

But i think we should do such math when we are free 'coz we enjoy olympiad maths.

Can you please suggest me some resources for inmo level geometry and some important topics in geometry to be studied?

Harsh Shrivastava - 4 years, 6 months ago

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@Harsh Shrivastava Do you get selected in RMO?

I got selected.

Priyanshu Mishra - 4 years, 6 months ago

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@Priyanshu Mishra Yes.Let's start the INMO Board!!

Harsh Shrivastava - 4 years, 6 months ago

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@Harsh Shrivastava Oh congratulations.

I have already started that. Check here.

https://brilliant.org/discussions/thread/inmo-2017-board/?ref_id=1273098

Priyanshu Mishra - 4 years, 6 months ago

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@Priyanshu Mishra I think you should post a new note because that thread has died.

Harsh Shrivastava - 4 years, 6 months ago

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@Harsh Shrivastava Ok i will post a fresh one.

Priyanshu Mishra - 4 years, 6 months ago

@Nihar Mahajan Also,how's ya' iit prep going on?

How was KVPY?

Harsh Shrivastava - 4 years, 6 months ago

I have RMO on 23rd.

Ayush Pattnayak - 4 years, 8 months ago
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