This year’s (2013) RMO paper of Maharashtra and Goa Region .
(1) Find all positive integers m such that (m−1)! is divisible by m.
(2) H is the orthocentre of △ABC, D is any point on BC if a circle described with centre D and radius DH meets AH produced in E, Prove that E lies on the circumcircle of △ABC.
(3) Suppose △ABC is an acute angled triangle with AB<AC. Let M be the midpoint of BC. Suppose P is a point on side AB such that, if PC intersects the median AM at E, then AP=PE.Prove AB=CE.
(4) Let x and y be real numbers such that x2+y2=1
Prove that x2+11+y2+11+1+xy1≥1+4(x+y)23
(5) Let an be number of sequences of n terms formed using the digits 0,1,2 and 3 in which 0 occurs an odd number of times. Find an
(6) Find all positive integers n such that the product of all the positive divisors of n is equal to n3.
#RMO
#Exams
#HelpMe!
#Proofs
#India
#Competitions
#MathCompetitions
#MathProblem
#Math
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
...\]
to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
Find all positive integers n such that the product of all the positive divisors of n is equal to n^3
Log in to reply
Simply find "n" who have 6 positive divisors(including n itself) thus giving 3 pairs that give product exactly n so that product of all divisors being n3........ hence n=p12.p2 OR n=p5 OR 1
Log in to reply
How come you have put more than 5 tags?@Aditya Raut
Log in to reply
Log in to reply
@Aditya Raut
Oh, btw congrats for clearing RMO.The third question is very simple one. One needs to use the result that when two cevians intersect the sides of triangles in the ratio m and n respectively, then they divide each other in the ratio m(n+1)/n and n(m+1)/m. Then the question becomes very simple.
Log in to reply
Yes and that formula can be proved simply by Using B.P.T. or Basic Proportionality Theorem...
Log in to reply
which books did you use for RMO? @Aditya Raut
PlZ give this ques Sol. Actually I am not able to solve this
Can someone tell me where I can read more about this, and what is the name of this theorem?
I solved this one using B.P.T and similar triangles.
Answer to 1st question:-
m∈N− {4,p}
where p is prime. (All prime numbers are discarded)
Log in to reply
To cancel all the primes, We can use Wilson's Theorem.
how did we solve question number 4
Answer to 6th question:-
All n such that n=p12×p2 OR n=p5 OR 1
where p denotes prime.........
Answer to the 1st one : (m - 1)! is divisible for all positive integers except 4 and primes.
Answer to the 6th one : If you consider n and 1 to be the divisors too, the answers are p^5 and p^2 * q , p and q are primes.
Answer to the 4th one: Simplify the L.H.S and R.H.S of the inequality, such that both the sides contain only xy. After that, using the fact that ( x -y )^2 is always greater than or equal to zero, find out the max value of xy. Plug the max value of xy in the inequality.
Log in to reply
I used Cauchy's inequality to get the results.
I used Titu's Lemma
Yeah....we got xy≤21 by A.M- G.M inequality to numbers x2,y2
6th problem also has 1as it's solution because positive divisor of 1 is 1 which satisfies product of divisors = 13
1 and 6 have answers there are infinite solutions
i will try
question no. 5 is also very easy.
I'm selected for the second level. Are you ???
Why's this incomplete? @Aditya Raut -Care to complete it?
Log in to reply
DONE .... THANKSSS .... If you hadn't commented, i wouldn't have known that this paper was later made into half paper.... that might be a mistake by some staff most probably...
Log in to reply
Thanks a ton!!!!! :)
Hi Again! @Aditya Raut -I guess I'd be appearing for RMO dis'yr (That depends on my pre-RMO performance though :P). I;d like to have some tips and prep-method from you. I know that the MG-RMO is much different and easy compared to TN-RMO( which is why we have an equally tough Pre-RMO :P ). ..but yet...You're too good in math...so....even book references would be much appreciated. And-another thing- could you tell me a good resource to learn parametric substitution to solve algebraic equations? I recently noticed this in some problem on this site- and found it fun...I want to know more...Thanks :)
Log in to reply
If you don't mid give me your email ID plz
And when you reply to this, please mention me. (Hope you'll reply to say thanks :P LOL)
For RMO tips, I recommend you to do what Dinesh said in the discussion of this problem , because me and Dinesh are classmates and I have already said that do what he said (though he didn't clear RMO with me last year, he has double potential to do that).
Book references that I have been using are Inequalities- An Approach Through Problems (author B. J. Venkatachala),
Applied Combinatorics (author Alan Tucker)
Elementary Number Theory (author David M. Burton)
Problem Solving Strategies (author Arthur Engel)
An Excursion in Mathematics (by Bhaskaracharya Pratishthana, Pune)
This one i got from Bhaskaracharya Pratishthana for clearing RMO (The co-oridinator of RMO in Maharashtra and Goa region)
IMO problems (author Istvan Reiman)
Try previous year RMO papers, that is the most useful thing. Don't look at solutions till you have tried it a lot. And most important, keep calm, because in RMO, every question is solvable, but the TRICK doesn't CLICK at the time, so think on small things.
That's all i can tell, if you want to know more books, or have all the above books for free
(To get these books, I paid ₹ 3379/− , but you can get them for free)
Just go to libgen.org or go to bookzz.org and search the book, i am sure you'll get for free. (I downloaded a very costly book named "Learn Python the hard way" for free from here).
@Krishna Ar , @Dinesh Chavan
Log in to reply
Log in to reply
[email protected]
Anytime ! Wanna be friends ? Gmail-@Aditya Raut . I shall try to see the parametric stuff related things on net. Thx again! :) Shall I send you a mail? I guess I saw it in the sol of a problem?
Wow...Thanks A lot for replyingLog in to reply
[email protected] instead of '[email protected]', because my yahoo account is related to brilliant and so it is stuffed with emails of "someone liked/reshared/followed" , so for our communication, i prefer GMAIL. Same Applies to my new friend @Satvik Golechha too, please note this.
Anytime, I am there for anyone who wants to be friends! By the way, please send me email if you want, atLog in to reply
please give me the proof of weierstrauss product inequality
Log in to reply
Here is your link :)
Log in to reply
what is the jensens inequality?
What is the answer to question 5?
Is my answer to question 5 correct? an=83n+1−3 if n is even and an=83n−1 if n is odd?
By the way, I have a few more questions. Was this the same paper for Pune region? Is Arthur Engel's book good?
@Aditya Raut How to solve the 4 th question can you tell
pls explain how to solve the 4th one
You can use cauchy and (x-y)^2 greater than or equal to 0 for 4th question
The third one is actually quite simple.......... Construct a line parallel to BC from P. Equate the ratio of AP and AB to the ratio of PE and EC ( This can be done by using B.P.T and similar triangles. )
How to solve the 2nd question?
where can I find answer key