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2 \times 3
2×3
2^{34}
234
a_{i-1}
ai−1
\frac{2}{3}
32
\sqrt{2}
2
\sum_{i=1}^3
∑i=13
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123
Comments
The result is not true if your semigroup does not have an identity. Consider the semigroup {n∈N:n≥2} under ordinary multiplication, which satisfies the cancellation laws but does not have an identity.
The result is not true for infinite unital semigroups. Consider the semigroup N under ordinary multiplication.
The result is true for finite unital semigroups. The cancellation laws guarantee that (for example) left multiplication by x∈G is injective. Why does that guarantee the existence of a right inverse for x?
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
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to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
The result is not true if your semigroup does not have an identity. Consider the semigroup {n∈N:n≥2} under ordinary multiplication, which satisfies the cancellation laws but does not have an identity.
The result is not true for infinite unital semigroups. Consider the semigroup N under ordinary multiplication.
The result is true for finite unital semigroups. The cancellation laws guarantee that (for example) left multiplication by x∈G is injective. Why does that guarantee the existence of a right inverse for x?
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But same problem can we prove in this way by using this statemet that is in a group G a,b,x,y belongs to G ax=b and ya=b have unique solution