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The condition that you have given is for asymptotic convergence. Without an additional condition of ∣xn+1−a∣≤k∣xn−a∣ the limiting condition cannot be proved.
With my knowledge of dynamics, there seems to be no solution without apriori assumption that limn→∞xn exists and is finite.
@Janardhanan Sivaramakrishnan
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That's right, without any other conditions the only inequation we need to prove That a sequence converges to some value is the one You provided, and that's how we usually solve for the limits. Furthermore, we use This frequently when we have a sequence un satisfying:
un+1=f(un)
For some continuous and differentiable function f.
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∣xn+1−xn∣≤k∣xn−xn−1∣,∣xn−xn−1∣≤k∣xn−1−xn−2∣ Combining, ∣xn+1−xn∣≤k2∣xn−1−xn−2∣
This would imply that ∣xn+1−xn∣≤kn∣x1−x0∣.
Since, k∈[0,1], kn→0 as n→∞.
Hence, ∣xn+1−xn∣→0 as n tends to infinity.
The series is thus convergent.
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I did the same proof but my teacher told me it must be shown that lim(x_n)=a
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The condition that you have given is for asymptotic convergence. Without an additional condition of ∣xn+1−a∣≤k∣xn−a∣ the limiting condition cannot be proved.
With my knowledge of dynamics, there seems to be no solution without apriori assumption that limn→∞xn exists and is finite.
Log in to reply
un satisfying: un+1=f(un) For some continuous and differentiable function f.
That's right, without any other conditions the only inequation we need to prove That a sequence converges to some value is the one You provided, and that's how we usually solve for the limits. Furthermore, we use This frequently when we have a sequence