Set theory proofs

Could someone help me out with these set theory proofs? \(A\), \(B\) and \(C\) are sets, and the questions are independent of each other.

Q1. Show that if ABA\subset B, then CBCAC-B\subset C-A.

Q2. If P(A)=P(B)P(A)=P(B), show that A=BA=B.

Note: P(A)P(A) denotes the power set of AA.


Also, could you provide me an faster solution to this question? The question is 'Show that A=(AB)(AB)A=(A\cup B)\cap(A-B)'. My method is to assume that aAa\in A, and prove that a(AB)(AB)a\in (A\cup B)\cap(A-B), and hence say that A(AB)(AB)A\subseteq(A\cup B)\cap(A-B), and prove vice versa. I find this method extremely lengthy. Is there a faster method?

#Algebra

Note by Omkar Kulkarni
6 years ago

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1 vote

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Comments

Q3: Let's suppose that P(A)=P(B)\mathscr{P}(A)=\mathscr{P}(B).

Let xA x \in A. Then CP(A):xC \exists C \in \mathscr{P}(A) : x \in C . Let CP(A) C \in \mathscr{P}(A) be in that conditions. By hypothesis, we have that CP(B) C \in \mathscr{P}(B) , this means that xCB x \in C \subseteq B , so xB x \in B.

Now, yB y \in B. Then DP(B):xD \exists D \in \mathscr{P}(B) : x \in D . Let DP(B) D \in \mathscr{P}(B) be in that conditions. By hypothesis, we have that DP(A) D \in \mathscr{P}(A) , this means that yDA y \in D \subseteq A , so yA y \in A.

In conclusion, A=BA=B .

Paulo Guilherme Santos - 5 years, 9 months ago

Q1: Show that if xCBx \in C \setminus B, then xCAx \in C \setminus A.

Q2: This basically says that if you are given P(A)P(A), then you can uniquely determine the set AA. For example, if P(A)={,{1},{4},{5},{1,4},{1,5},{4,5},{1,4,5}},P(A) = \{\emptyset, \{1\}, \{4\}, \{5\}, \{1,4\}, \{1,5\}, \{4,5\}, \{1,4,5\}\}, then what is AA? You just need to generalize this idea.

As for your last question, I don't think there's a faster way. That's the traditional approach for showing that two sets are equal. Sometimes, you may be able to use some identity that you have proven before, but I doubt that's the cas here.

Jon Haussmann - 6 years ago

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Oh okay. Makes sense. Thank you! I'll come back to you with the second one if I don't get it.

Omkar Kulkarni - 6 years ago
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