SIMPSON'S PARADOX

SUPPOSE THERE ARE TWO PERSONS, NAMELY A AND B. SUPPOSE THEY ARE THE STUDENTS AND ARE GIVING THE EXAMINATION. ON DAY 1, A SCORED 63/90 (63 MARKS OUT OF 90). SO HE SCORED 70%. ON DAY 1, B SCORED 8/10 (8 MARKS OUT OF 10). SO HE SCORED 80%. SO ON DAY 1, B WINS AS HE IS 10% AHEAD OF A.

ON DAY 2, A SCORED 4/10 (4 MARKS OUT OF 10). SO HE SCORED 40%. ON DAY 2, B SCORED 45/90 (45 MARKS OUT OF 90). SO HE SCORED 50%. SO ON DAY 2, B WINS AS HE IS 10% AHEAD OF A.

CONSIDER TOTAL MARKS SECURED BY THEM. A SCORED 63+4=67 MARKS OUT OF 100. SO HE SCORED 67%. B SCORED 8+45=53 MARKS OUT OF 100. SO HE SCORED 53%. SO CONSIDERING OVERALL PERCENTAGE, A WINS AS HE IS 14% AHEAD OF B.

BUT HOW COULD THIS HAPPEN, B WINS ON DAY 1 AND DAY 2. HOW COULD HE LOSE WHEN WE CONSIDER OVERALL MARKS?

ISN'T IT INTERESTING!!!!!!!

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Comments

Horla asd - 6 years, 7 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$