Solve this....

The sum of 5 different positive integers is 90. What can be the 2nd largest number of the 5 at most?

These were the options qiven when I tried the question:

$1)$ 82

$2)$ 43

$3)$ 34

$4)$ 73

I got $41$ as the answer but didn't found them in options so was confused. Let me know what answer do you guys get.

PLEASE give it a try.

Thanks.

#NumberTheory #NMTC

Easy Math Editor

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Comments

Aditya Chauhan - 5 years, 10 months ago

I got the same.

Akshat Sharda - 5 years, 10 months ago

I think it has considered zero to be a +ve integer as well. That way the answer would be 43.

But considering zero is neither +ve nor -ve, the correct answer should definitely be 41.

Tapas Mazumdar - 5 years, 10 months ago

Tried it, and got 41. So maybe it's a mistake and someone accidentally put 43 instead of 41?

tytan le nguyen - 5 years, 10 months ago

Kushagra Sahni - 5 years, 10 months ago

If we consider 0 then it comes to be 43 but in other case we have 42+41+4+2+1.

Keshav Bassi - 5 years, 9 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$