solve this

X = 2 + 2^(2/(3 ))+ 2^(1/3) So, x^3-6 x^2+6= ???

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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
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`\boxed{123}`	$\boxed{123}$

Comments

Given $x = 2+\sqrt{2}+\sqrt[2]{2}\Rightarrow (x-2)^3 = \left(\sqrt{2}+\sqrt[2]{2}\right)^3$

We Get $x^3 -8-6x(x-2) = 2+2^2+3\times 2 \left(\sqrt{2}+\sqrt[2]{2}\right) = 6+6x$

Now Solve after that....

jagdish singh - 7 years, 6 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$