Solve this!

Look Closely...it's a quadratic equation. Now find the number of solutions it has.

#HelpMe! #MathProblem #Math

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Comments

take L.H.S=f(x), and it is easy to show that f'(x)=0; for all x. ie, f(x)= k = f(-a)= 1, so for all x f(x)=1;

NIDHIN KURIAN - 8 years, 1 month ago

That is a good observation. A simpler approach would be to make common denominator and consider the quadratic polynomial in $x$ , and easily see that the quadratic coefficient and linear coefficient are both 0.

Calvin Lin Staff - 8 years, 1 month ago

If the L.H.S=f(x) (if none of the a,b,c's are equal to each other) then f(x)=1 for all x in R. So f(x)-1=0 for all x in R. Thus f(x)-1=p(x) is the zero polynomial and not a quadratic.

Samuel Queen - 8 years, 1 month ago

its, not a quadratic equation as such because it has 3 real roots

NIDHIN KURIAN - 8 years, 1 month ago

yah! u r right its an identity............ just for confusion.

DIKSHA VERMA - 8 years, 1 month ago

yes, my answer of -a, -b, -c is not correct as indeed it is an identity function the equation is satisfied for all x belonging to R.

NIDHIN KURIAN - 8 years, 1 month ago

the roots are -a,-b,-c, assuming a, b, c are distinct real numbers

NIDHIN KURIAN - 8 years, 1 month ago

how did you got the answer? plzzz explain....i'm not able to solve! :|