Something that's confused me in physics and i need help please

If there's an object on the floor and I displace it upwards by H. then work done by gravity is -mgH and work done by me is mgH. If the force done by me is mg and the force by gravity is -mg , then how did object get displaced in the first place?

#Mechanics

Easy Math Editor

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Comments

@Andrew Mathew you have not done a force .
You have applied a force in upward direction which is greater than $mg$ .
And therefore the resultant force is in upward direction .Therefore the block has moved upwards

A Former Brilliant Member - 11 months, 4 weeks ago

if i applied a force greater than mg and displaced it by H then how is the work done equal to mgH it should be greater than mgH

Andrew Mathew - 11 months, 3 weeks ago

@Andrew Mathew Work done is depending upon change in height ,not on how much force you are applying on that block.

A Former Brilliant Member - 11 months, 3 weeks ago

@A Former Brilliant Member – The work done by gravity depends on the change in height. The work done by the force you exert is independent of this change in height.

Rohan Joshi - 4 months, 2 weeks ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$