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@Agr Amul
–
Yes. "The Projection of P onto AB is X" means "Drop a perpendicular from P to AB, intersecting AB at X".
Write out the equations of Pythagorean theorem. For example, XB2+BY2=OB2. You should have 4 equations. Does that help you solve for the sides? Why, or why not?
Note: I am not claiming that there is a unique set of solutions. I'm merely guiding you down what is the next sensible / logical step to take. It is not guaranteed that this must lead to a solution.
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
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or_italics_
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or__bold__
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to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
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How is this going to help? We can just get the value of x, nothing else.
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Great, that's a start. What can we do next?
If X, Y are the projections of O onto AB, BC, can we find AX, XB, BY, YC?
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Write out the equations of Pythagorean theorem. For example, XB2+BY2=OB2. You should have 4 equations. Does that help you solve for the sides? Why, or why not?
Note: I am not claiming that there is a unique set of solutions. I'm merely guiding you down what is the next sensible / logical step to take. It is not guaranteed that this must lead to a solution.
Log in to reply