Special Relativity formula

Hey guys, there appears to be a bit of a discrepancy between Brilliant's version of the time dilation formula and the formula on the internet. Following their reasoning, T'(moving frame) = T/y. which will mean that the observer in the moving frame will record less time than the stationary observer, but a video on crash course physics says that T' = yT, which means that the moving observer will record more time than the stationary observer, so which is right? Who has misunderstood the point of relativity here?

Easy Math Editor

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Comments

Hey @Quantum pixel, happy to clarify and adjust if there's a typo. Would you mind linking to the video and the Brilliant quiz you're referring to?

Josh Silverman Staff - 10 months ago

Crash course physics video https://www.youtube.com/watch?v=AInCqm5nCzw&t=279s

Brilliant quiz https://brilliant.org/practice/boosting-between-frames/?p=6

Quantum pixel - 9 months, 4 weeks ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$