Square of numbers near 50

If a number is in the form of (50–n)^{2} suppose →45^{2} then the short trick of getting the answer is : \frac{(45–5)}{2}'/'5^{2} . Remember here '/'doesnot means divide,it means the distinction or \boxed{digits are separated} so my answer becomes 20/25 which means 2025 is the answer. Check it out !

#Logic

Easy Math Editor

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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

Hey Here's a little reply XD For -10 < x < 10 (50 + x)^2 = 2500 + 100x + x^2 i.e. First 2 digits = 25 + x Last 2 digits = x^2 Very basic identity manipulation e.g. 55^2 = (50 + 5)^2 = 3025 See? 30? 25? XD

Alanta Kwoks - 4 years, 9 months ago

Are u telling this to me?? First read what i have written then speak. Lol . Telling me identity

MaFiA maNiAc - 4 years, 9 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$