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2 \times 3
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If we stipulate that both sides have to have at least two terms, then I get some solutions:
62+⋯+54272+⋯+12282+⋯+572112+⋯+152142+⋯+542152+⋯+912202+⋯+302222+⋯+942222+⋯+962272+⋯+592=203+⋯+243=63+73=83+⋯+223=73+83=63+⋯+213=303+⋯+363=93+⋯+133=313+⋯+373=173+⋯+333=13+⋯+223
And there are lots more.
By a (very unsophisticated) search for positive integer solutions to the polynomial equation
6x(x+1)(2x+1)−6y(y+1)(2y+1)=4z2(z+1)2−4w2(w+1)2,
where I throw out solutions with x−y≤1 or z−w≤1.
# -*- coding: utf-8 -*-"""Created on Wed Nov 22 16:41:38 2017@author: Michael Fitzgerald"""defbuild_dict(n,s,sum_x):foriinrange(max_,1,-1):forjinrange(min_,i):forkinrange(j,i+1):ifi<=j:breakifj!=k:key_='%d-%d'%(j,k)else:key_='%d'%ks+=k**nsum_x[key_]=ss=0returnsum_xmin_=1#Enter min of rangemax_=300#Enter max of rangesum_sq={}sum_=0sum_sq=build_dict(2,sum_,sum_sq)sum_cube={}sum_=0sum_cube=build_dict(3,sum_,sum_cube)#print sum_cubematching=[[sum_sq[a],a,b]forainsum_sqforbinsum_cubeifsum_sq[a]==sum_cube[b]]sorted_list=sorted(matching,key=lambdax:x[0])foriinsorted_list:print'Sum: %d; Squares range: %s; Cubes range: %s'%(i[0],i[1],i[2])
The difference of the squares of two consecutive triangular numbers will be a perfect cube whose cube root is equal to the difference between those triangular numbers. So, 3^3 + 4^3 = (6^2 - 3^2) + (10^2 - 6^2) = 91 = 1^2 + 2^2 + 3^2 + 4^2 + 5^2 + 6^2. Or generalized, the sum of the cubes of two consecutive numbers is obtained; (L-M)^3 + [(L-M)+1]^3 = (L^2 - M^2) + (N^2 - O^2) where n-o = [(L-M)+1] and (N-O)-1 = L-M. Does that help at all?
I'm curious about these things, but are they coincidental or are there deeper algebraic reasons for this? Say rooted in abstract algebra or number theoretical grounds? For example, Fermat's Last Theorem looked simple when stated, but the proof required techniques deemed not available during Fermat's time, but somehow involved elliptic curves and such things rooted in abstract algebra.
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
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to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
If we stipulate that both sides have to have at least two terms, then I get some solutions: 62+⋯+54272+⋯+12282+⋯+572112+⋯+152142+⋯+542152+⋯+912202+⋯+302222+⋯+942222+⋯+962272+⋯+592=203+⋯+243=63+73=83+⋯+223=73+83=63+⋯+213=303+⋯+363=93+⋯+133=313+⋯+373=173+⋯+333=13+⋯+223 And there are lots more.
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How u got these?
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By a (very unsophisticated) search for positive integer solutions to the polynomial equation 6x(x+1)(2x+1)−6y(y+1)(2y+1)=4z2(z+1)2−4w2(w+1)2, where I throw out solutions with x−y≤1 or z−w≤1.
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The difference of the squares of two consecutive triangular numbers will be a perfect cube whose cube root is equal to the difference between those triangular numbers. So, 3^3 + 4^3 = (6^2 - 3^2) + (10^2 - 6^2) = 91 = 1^2 + 2^2 + 3^2 + 4^2 + 5^2 + 6^2. Or generalized, the sum of the cubes of two consecutive numbers is obtained; (L-M)^3 + [(L-M)+1]^3 = (L^2 - M^2) + (N^2 - O^2) where n-o = [(L-M)+1] and (N-O)-1 = L-M. Does that help at all?
≠
I'm curious about these things, but are they coincidental or are there deeper algebraic reasons for this? Say rooted in abstract algebra or number theoretical grounds? For example, Fermat's Last Theorem looked simple when stated, but the proof required techniques deemed not available during Fermat's time, but somehow involved elliptic curves and such things rooted in abstract algebra.