I just figured out this amazing way of squaring numbers with ones digit 5. Suppose you need to find out the square of 35. Then simply square 5 and write down 25 at last and then multiply 3*3 and add 3.That is square the remaining numbers except 5 and add the same value.You will get 12.Since you can also write it as 3 (3) + 3 = 3 (1 + 3) = 3 *4. So,you may just as well multiply the next integer. You can now easily write 35^2 = 1225. In case of another no.,say 125,you take 25 at last and multiply 12 * 13.So,you have 15625. If you are more comfortable in squaring,simply square 12,you'll get 144 and then add 12,you will get 156.So,125^2 = 15625. Rule works for no. whose ones digit is 5. You will probably not find this anywhere else.It was something I came up with while randomly squaring integers.
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Very good that you rediscovered this yourself. You may be interested in knowing that square of any two and three digit numbers can be found as under. (10a±b)2 write square of a and then of b. (if b is 1, 2 , or 3, write its square as 01, 04 or09) to this ± 20 times a*b. Say 372=(30+7)2=949+20∗21=1369.372=(40−3)2=1609−20∗12=1369 Three digit number the same way 1272=(120+7)2=14449+20∗84=161291272=(130−3)2=16909−20∗39=16129With 5 at unit place it is easy. (10a+5)2=a∗(a+1)25.1252=(120+5)2=(12∗13)25=15625.
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Amazing! Thank you.
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I have made an addition.
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