Stucking in a Magnetism problem

Here is the problem taken from Pathfinder Physics Book
Here is my attempt

I have calculated magnetic field at that ring, now how to proceed?
Should I use the concept generating electric field due to changing of magnetic field.
Please help, Thanks in advance.

#ElectricityAndMagnetism

Note by Talulah Riley
9 months, 1 week ago

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1 vote

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Comments

@Steven Chase @Karan Chatrath

Talulah Riley - 9 months, 1 week ago

WTF, why I am not able to mention names? This bug should be fixed.

Talulah Riley - 9 months, 1 week ago

Yes, I think you need to apply the concept of an induced electric field. It is the resulting electric field that will cause the ring to rotate.

Karan Chatrath - 9 months, 1 week ago

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@Karan Chatrath ....

Talulah Riley - 9 months, 1 week ago

@Karan Chatrath sir the magnetic field is getting constant after dtdt time?
I don't think it will help?
What do you think , this is the main concept E=R2dBdt\vec{E}=-\frac{R}{2}\frac{d\vec{B}}{dt}
The magnetic field which I have obtained above is B=μ0σRωB=\mu_{0} \sigma R \omega
And it is constant

Talulah Riley - 9 months, 1 week ago

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Okay, I will try to work it out by myself in some time. Let me give this a thought.

Karan Chatrath - 9 months, 1 week ago

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@Karan Chatrath I have a special problem in this types of problems.
Jaise maine is type ke question ka solution dekh lia maan lo kahi se (but iska solution internet pe available nhi hai) , to mujhe ye samajh aa jaayega, but jab mai khud se solve karne jaauga to nhi hoga.
Even start bhi nhi hoga, please help me how to start this??

Talulah Riley - 9 months, 1 week ago

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@Talulah Riley Startt by calculating all forces on the particle and applying Newton's second law

Karan Chatrath - 9 months, 1 week ago

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@Karan Chatrath @Karan Chatrath ha ha ha nhi ho rha sir, difficulty aa rhi?
The problem is that magnetics field se particle rotate karega, phir vaha pe drag lagega, bahut confusion ho rha,
Bas start kaise karu ye bata dijiye please

Talulah Riley - 9 months, 1 week ago

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@Talulah Riley Newton's second law:

ma=q(v×B)kvm \vec{a} = q(\vec{v} \times \vec{B}) -k \vec{v}

You will get two equations for accelerations along X and Y. Solve those differential equations. The equations will be linear so you can solve for an exact solution.

Karan Chatrath - 9 months, 1 week ago

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@Karan Chatrath @Karan Chatrath Thank\Huge Thank You\Huge You SO\Huge SO MUCH\Huge MUCH

Talulah Riley - 9 months, 1 week ago
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