Surface Area Problem caused dilemma in my AP Calculus BC class

Hey guys. I could some help. This problem caused an issue in my class and I just want to see how everyone goes about doing it and the answer they get:

Find the surface of area of the solid generated from rotating sin(x)\sin(x) on the interval of 0 to π\pi around the yy-axis.

#Calculus

Note by Andrew Tawfeek
5 years, 3 months ago

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Comments

I think that the method of cylindrical shells would work best here. The volume VV will be

V=0π2πxydx=2π0πxsin(x)dxV = \displaystyle\int_{0}^{\pi} 2\pi xy dx = 2\pi \int_{0}^{\pi} x\sin(x) dx.

Evaluating by parts, we let u=x,dv=sin(x)dxdu=dx,v=cos(x)u = x, dv = \sin(x) dx \Longrightarrow du = dx, v = -\cos(x), and so

V=2π(xcos(x)+cos(x)dx)=2π(xcos(x)+sin(x)V = 2\pi(-x\cos(x) + \displaystyle\int \cos(x) dx) = 2\pi(-x\cos(x) + \sin(x)),

which when evaluated from x=0x = 0 to x=πx = \pi comes out to V=2π(πcos(π)0)=2π2V = 2\pi (-\pi \cos(\pi) - 0) = \boxed{2\pi^{2}}.

We could also have used the disc method but that would have been a bit more complicated, as the integral would be of the arcsin function. What was the issue within your class?

Brian Charlesworth - 5 years, 3 months ago

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I'm sorry -- but we were attempting to solve for the surface area, not the volume!

Andrew Tawfeek - 5 years, 3 months ago

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Oh! Sorry. I don't know why I read "surface area" as "volume" the first go around. For the part of the solid generated that is strictly above the xzxz-plane the surface area integral is

A=0π2πx1+cos2(x)dxA = \displaystyle\int_{0}^{\pi} 2\pi x\sqrt{1 + \cos^{2}(x)} dx,

which I believe can only be solved using elliptic integrals, which would be beyond the scope of an AP course. So now I understand what the issue in your class was. (WolframAlpha gives a value of 37.7038.)

Brian Charlesworth - 5 years, 3 months ago

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@Brian Charlesworth Ahh yes, thank you! There was a whole debacle about how to go about solving this and I didn't post the steps that were taken in the case that they were inaccurate. :)

Andrew Tawfeek - 5 years, 3 months ago
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