I am struggling with understanding https://nrich.maths.org/251.
To restate the problem,
If \(x\), \(y\) and \(z\) are real numbers such that: \(\begin{cases}x+y+z=5 \\ xy+yz+zx=3\end{cases}\) , What is the largest value that any one of these numbers can have?
In particular, I do not understand the first solution given, and while the second I am getting a grip with (creates a quadratic uses the discriminant inequality since , and are real numbers), would like to ask whether any classical inequalities can be used here, as I would be personally more satisfied with this.
The problem I had with applying inequalities I knew was that , and could be any real numbers, not just positive.
Any help/discussion would be much appreciated!
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The link u have referred is not opening, it says the page not found.However, u can see my solution to this problem : https://brilliant.org/problems/almost-vietas/#!/solution-comments/171217/
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Fixed btw
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yup
Thanks Vilakshan. I leant from both your and Sharky's answers.
actually u have put a dot by mistake in front of 251
okay ! great
Hey buddy is the answer 213?
i m getting 313 as maximum value and -1 as minimum value
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Yep same here! What was your method?
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but u said u are getting 213 . I used the same method which i referred to in the link i gave.
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313. I actually did not check the link out. Let me check it now
Oops! Sorry I am gettingLog in to reply
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