System Of Complex Equations - Add A Constraint

Suppose that \(z_1, z_2, z_3, z_4, z_5 \) are complex numbers which satisfy

{z1=z2=z3=z4=z5=1,z1+z2+z3+z4+z5=0,z1z2+z2z3+z4z5+z5z1=0 \begin{cases} |z_1| = |z_2| = |z_3| = |z_4| = |z_5| =1, \\ z_1 + z_2 + z_3 + z_4 + z_5 = 0, \\ z_1 z_2 + z_2 z_3 + z_4 z_5 + z_5 z_1 = 0 \\ \end{cases}

What can we conclude about z1,z2,z3,z4,z5 z_1, z_2, z_3, z_4, z_5 ?


You may refer to System Of Complex Equations, in which Mursalin and Prakhar showed that if only the first 2 conditions are true, then we can't really conclude too much. Other than a regular pentagon, the 5 points could be that of an equilateral triangle along with a diameter, or even 5 'somewhat random' points on the circle (no easy description).

How does adding in the third condition help us?

#Algebra #ComplexNumbers #SystemOfEquations #ArgandDiagram

Note by Calvin Lin
7 years, 1 month ago

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Comments

Rearranging the third equation z2(z1+z3)=z5(z4+z1)z_2(z_1+z_3)=-z_5(z_4+z_1) and taking modulus on both the sides, one obtains: z1+z3=z1+z4|z_1+z_3|=|z_1+z_4|. This means that the distance of z1z_1 from z3z_3 and z4z_4 is same. Join the centre with z1z_1. Call this line OA. Now, OA divides the circle into two semicircles. z3z_3 and z4z_4 obviously cannot lie on the same semicircle. They lie symmetrically about OA on different semicircles. Further divide the semicircle in four quadrants. Here is an image to go with my explanation:

Notice that z3z_3 and z4z_4 cannot lie in 1st and 4th quadrant. If they did, z3+z4z_3+z_4 would be along z1z_1 and z1+z3+z4>1|z_1|+|z_3+z_4|>1 but since z2+z5<1|z_2+z_5|<1, it would be impossible to satisfy the second condition. So, z3z_3 and z4z_4 must lie in 3rd and 2nd quadrants.

By a similar argument, z2z_2 and z5z_5 must lie in 3rd and 2nd quadrant. They too must lie symmetrically about OA and on different sections of semicircles.

Hence, it is a pentagon but not necessarily a regular one.

I am not sure if this is correct, though.

Pranav Arora - 7 years, 1 month ago

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This is a great piece of analysis!

I just realized that I screwed up the 3rd equation, and missed out the z3z4 z_3 z_4 term. Let me post a new note to reflect that.

Calvin Lin Staff - 7 years, 1 month ago

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Ah!

Thanks Calvin! :)

Pranav Arora - 7 years, 1 month ago

They may be 5 th roots of unity

Kanthi Deep - 7 years ago

They may be vertices of regular Pentagon inscribed the in a unit circle

Kanthi Deep - 7 years ago
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