Since we have to compete in jee in an all India level , it is quite obvious that we want the views of others , we want to know about our competitors.
So I have created this as a Communication platform for all those preparing for IIT - JEE.
You can talk to the ones personally by mentioning their link. And giving them the time when you will be online .
you can ask general questions.
you can keep your communication personal by deleting it after your work is over.
Anyone can join this chat room and can even invite his friends . For joining just save this note with you (optional).
You can even ask your doubts. In any chapter(Restriction :you cannot discuss solution to Brilliant questions here , but you can share the link and ask them to come there )
I see ,we don't always get a reply to our question , but if we all be at a single chat room we would definitely get a reply
Since this one is becoming bulkier , here is the continuation Click here
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
> This is a quote
\(
...\)
or\[
...\]
to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
Doubt:
Please give a hint.
A uniform rid of length L lies on a smooth horizontal table.A particle moving on the table strikes the rod perpendicularly at one end and stops. Find the distance travelled by the center of rod by the time it turns through a right angle.
Log in to reply
Use the following equations to find ω:
Conservation of linear momentum
Conservation of angular momentum (about a point just above the COM of the rod, in the air, so that the point taken is stationary wrt ground and there is no angular impulse)
Then use θ=ωt to get the time taken by it to rotate through θ
And finally, S=vt, where v is the velocity of the COM of the rod after collision, to find the distance travelled
Log in to reply
Ohk got it!
Thanks a ton.
Log in to reply
Log in to reply
Noatter how hard I try, I can't do physics independently without any aid.
General question:
We all are usually confused whether the book we are referring is nice or not.........especially in the critical month before jee advanced.........let's here share the books we prefer along with a reason why we prefer it
Log in to reply
Maths - cengage (lot of q to practice along with solutions)
Physics - cengage (lot of q to practice along with their solutions, nice theory )
Chemistry-
Physical- P bahadur (Everything in few pages)
Inorganic - NCERT ( Best explanation)
Organic - Cengage ( Authentic theory)
Log in to reply
Physics- HC Verma (Most Authentic Theory and No errors at all and best theoretical Problems are framed from It Only) DC Pandey (Practice Nice questions with solutions)
Chemistry- RC Mukherjee (Physical- Has Almost all the variety of problems and important concepts)
Solomon's And fryhle (Organic- Detailed Explanantion and nice subjective problems)
Inorganic- its none of my buisness ! :P (but still i like ncert)
Maths- I dont get time to solve problems of maths from books (my coaching sheets, packages and archive are more than enough i think)
But still i refer to TMH For algebra for some mind bending problems and arihant for calculus for good explanation of concepts
Log in to reply
@Prakhar Bindal I have found a mistake in HC Verma.
Log in to reply
Log in to reply
Log in to reply
@Prakhar Bindal what is the color of the cover page of soloman and fryle
Log in to reply
This book
http://www.amazon.in/Solomons-Fryhles-Organic-Chemistry-Advanced/dp/8126541814?tag=googinhydr18418-21
Log in to reply
Log in to reply
http://www.flipkart.com/organic-chemistry-english-7th/p/itmdmyjz99fnszs6 ]\
Log in to reply
Log in to reply
same here but I prefer Ms Chauhan for organic
I would say,
Maths-Cengage(JEE type questions)
Physics-Resnick Halliday,Feynman(awesome concepts),HC Verma(conceptual questions),DC Pandey(JEE type),Irodov,Krotov(for high thinking)
Physical Chemistry-P Bahadur(many problems)
Inorganic Chemistry-JD Lee(concepts),OP Tandon(mostly for facts)
Organic Chemistry-Solomons(concept),Himanshu Pandey(many JEE type questions)
To be honest, for physics, every book copies from Irodov,Krotov,Resnick Halliday(including HC Verma,DC Pandey) so I would suggest to solve many questions from these books even if they are difficult.
Physics- HC Verma , i.e irodov (sometimes) ,arithant publication by d.b. singh (head of science centre kota) vidyamandir modules, past 37 year iit jee questions, NCERT chemistry- i'm very poor at it, i don't really care but sometimes read my modules. NCERT maths- vidyamandir modules, past 37 year papers , TMH ,NCERT higher algebra (hall and knight) i'm not that much of a studious kid :)
Thanks a lot @Aniket Sanghi
@Aniket Sanghi @Prakhar Bindal Thank you both :D
What is the exam pattern of JEE 2017?
Log in to reply
you never know jee pattern even 1 day before JEE exam (adv. obviously!)
Log in to reply
Yes you are right. No one expected last year's pattern.
What is the exam pattern of JEE 2020? :P
Log in to reply
What is the exam pattern of JEE 2018?
Log in to reply
Is there any PDF or eBook which can help me improve my Coordinate Geometry for JEE Advanced? Since it's right around the corner and is generally where I lose marks in Maths, I'm wondering if there is any such resource or even a good question bank or something of the sort which can help me make it my strong point (most people say it's the easiest part of Maths).
I want to clear a doubt in this question
please read my comment and tell where i am going wrong.
Thanks.
Salute to the person who got the idea to Cretate this chat room . please can anyone tell the person who created this chat room . a wonderful idea . thank-you this chat room helped me a lot
Log in to reply
Thanks! I hope it will be helpful to all :)
A good mechanics problem :
A weightless rod of length l with a small load of mass m at the end is hinged at point as shown in the figure and occupies a strictly vertical position, touching a body of mass M. A light jerk sets the system in motion. For what mass ratio M/m will the rod form an angle x=30∘ with the horizontal at the moment of the separation from the body?What will be the velocity u of the body at this moment? Friction should be neglected.
Please help me with this problem.
@shubham dhull @Prakhar Bindal @Aniket Sanghi
Log in to reply
M/m = 4 v = (1/2)(gl/2)^0.5
Log in to reply
why don't u come over slack ?
Doubt: A small object is at rest on the edge of a horizontal table. it is pushed in such a way that it falls off the other side of the table, which is 1 m wide, after 2 s. Does the object have wheels?
Log in to reply
Average speed = total distance/total time. Therefore the average speed of the object is 1m/2s = 0.5 ms-1. We assume that the frictional force is constant such that the object decelerates uniformly, so we can say that 'average v = 1/2(initial v + final v)' From here, we can see that the initial speed cannot be greater than 1 ms-1, because 'final v' is more than or equal to 0 ms-1.
'Acceleration = (final v - initial v)/t', thus the magnitude of the object's acceleration is at most 0.5 ms-2. Frictional force = uN = umg, so frictional acceleration = F/m = ug, which is at most 0.5 ms-2 in this case. This means that 'u' cannot be greater 0.5/9.81 = 0.05. This is much smaller than the coefficients of friction between ordinary materials, and therefore it is very likely that the object does not slide, but that it has wheels and rolls. [adapted answer from source]
I also came across this question once this was the solution I found
Doubt : Please suggest some method to proceed-
First excitation potential of a hydrogen like species is 15eV. How can i possibly calculate energy if im given potential?Can someone let me know how to calculate energy of second orbit using this data ?
Log in to reply
I guess you know that energy of the n(th) Bohr orbit Is given by,E=−13.6(z/n)2eV=E(1)/n2.Where E(1) is the energy of the ground state.Hence E(2)=E(1)/4.and Thus E(2)−E(1)=15.Hence E(2)=−5eV
Log in to reply
I know that already and you cant take z=1 as its not specified.Secondly,i have to convert potential to energy.Tell me how that is done.Dont just post answers for the sake of it.
Invitation to @Prakhar Bindal @Gauri shankar Mishra @Aditya Kumar @aryan goyat @Mayank Singh and all who are interested are welcomed
Log in to reply
Thats a nice Initiative
Log in to reply
Great work
@aryan goyat
@Anshul Sanghi @ANSHUL SHRIVASTAVA @Harsh Shrivastava @Ashish R. Nair @Naman jain @Hargun Singh @Jyotisman Das
Log in to reply
@Calvin Lin @Andrew Ellinor @Ronak Agarwal @Nishant Rai @Sandeep Bhardwaj @ Deepanshu Gupta @David Mattingly
You all are experts and our seniors, We need and expect help from you .............
Log in to reply
@Adarsh Kumar @Kalash Verma @Nihar Mahajan
@Gautam Sharma @Pranshu Gaba @Vighnesh Shenoy @Abhineet Nayyar @Akul Agrawal @Rishabh Deep Singh @Rishabh Cool @Surya Prakash
How is your study going?
Nice
Is reading NCERT for inorganic enough?
Log in to reply
We are told that's enough for rest our fiitjee materials fill the vacant spaces
i dont think so
JD LEE + NCERT + Your institute's notes + Previous years papers = total JEE advanced inorganic chemistry
Log in to reply
Thanks I was doing JD LEE now. I was not sure whether that level would come. Now I shall read it more seriously.
I have 2 doubts. Firstly, in this Physics question question, the answer comes out as R23T2P⋅g, right? Secondly, in this Maths question, is there any better way of solving it other than taking partial derivatives, solving the simultaneous equations in x,y and plugging them in to get the answer?
Log in to reply
For the first one,the answer comes out as R23TPg because, it is a bubble and as there are two layers, while solving we have to take 2∗2π∗R.
What is adv.
Log in to reply
What are you asking?? Be clear
A common doubt : How to prepare inorganic chemistry and from where
@Sandeep Bhardwaj
I see that many students find themselves weak in chemistry , so, let's practice chemistry
A person who will answer the question correctly with its solution will have the right to post the next question, followed by another.and sequence would go on ............
Log in to reply
1 st question : how many radial nodes are present in the orbital represented as : n = 5 , l = 2 , m = 0.
Log in to reply
number of radial nodes = n-l-1 = 2.
Number of angular nodes = l = 2
Total Nodes (Excluding the one at infinity) = 4
Total Nodes (Including Infinity one) = n = 5
Log in to reply
Log in to reply
Log in to reply
Log in to reply
Log in to reply
Log in to reply
Log in to reply
@aryan goyat @Mayank Singh
Log in to reply
Log in to reply
Log in to reply
Log in to reply
Log in to reply
Log in to reply
Log in to reply
Log in to reply
And were you knowing aryan goyat is of our age (I thought he is 1 year ahead)
you have asked here radial nodes which is n-l-1 may it be 5z2.
Log in to reply
Log in to reply
Log in to reply
Which Resnick Halliday is better? The one written exclusively for jee advanced or one which is not?
Log in to reply
Go for the original one. That'll help you for NSEP+JEE.
Log in to reply
https://www.flipkart.com/physics-volume-i-5th-english/p/itmdytmvygedvpch?pid=9788126510887&lid=LSTBOK9788126510887QNNK0T
Is this good?
Log in to reply
Log in to reply
If you have few mins to spare, can you please give me a review about your book? Thanks!
Log in to reply
Log in to reply
Best is Resnick Halliday Crane ( I will not suggest Walker neither do I criticise it).
i want to invite the most intelligent person here but i hope he comes(he is not much active here!) : @Rajbir Malik
Hi.😇
Log in to reply
Welcome ( Late response I know ! :P)
I am just plain regular math lover. Not much....😅 I am not preparing for the JEE, but would love to be the part of the discussion. ( I am an army cadet! )😁
@Aniket Sanghi @shubham dhull @Prakhar Bindal Can i also join your chat room?
If yes, then please tell me how?
Log in to reply
i have deleted my account there as i thought i am not doing justice to myself, watching po** every time and the spending time, chatting with people, whenever i was not doing that "thing mentioned above" . i feel pity when i think where i have fallen from a state science Olympiad topper to my current state . sorry for saying it here but i think you r my friends and i can let all my feeling with you ! :(
Log in to reply
It is not too late, you can mend yourself, i have seen many people mending their ways and being back on track.May God be with you !
Log in to reply
Log in to reply
Log in to reply
Please give some tips on how to solve paper?
Thanks!
Log in to reply
For your question i would rather say solving chemistry and bio first (they wont consume more than 30 minutes). the two markers are also theoretical . either you know or you dont. its not a good idea to spend time on thinking biology questions if you dont know the solution.
Then i would say move to physics or maths (personal choice) . i did physics coz i knew that i was strong at maths and it will take my rank up .
I Finished physics in about 45 minutes (including 2 markers). i was left with 1 hour 45 minutes of which i devoted 1 hour 30 minutes to maths thinking twice checking each step . it was also fruitful i got a perfect score 25/25 in maths
Then in remaining 15 minutes i had a good look at the whole paper (made some intelligent guesses and 2-3 i did by tukabazi)
All the best! :)
Log in to reply
Log in to reply
Consult your parents if needed.See you can come out of the dictch, since if you could not come out, then you might have not regretted.
But you are regretting and that's a positive sign and it means that you can recover back to your normal studies! :)
You just need to be in discipline for 1 week and then you will automatically be normal.
Its is never too late.
Be engaged in fruitful activities all day.
Thanks for reading this LONG post :P
Cheers!!
(I may sound an old teacher but i like to spread motivation, my freinds call me motivator baba :P)
Which chat room are you talking about , the one I mentioned above?
Log in to reply
Yes, when i click on join it says account disabled.
Log in to reply
Log in to reply
[email protected]
Log in to reply
Log in to reply
Plz add me too 😅
Log in to reply
No i'll not add u :P
Log in to reply
I'll add you tmmrw k?
Log in to reply
Log in to reply
Log in to reply
Log in to reply
Log in to reply
[email protected]
How do I increase my problem solving speed?
Log in to reply
If you are preparing for JEE Main 2018 Exam and in need to boost your speed for solving the questions, then one of the best option is attempting JEE Main previous year question papers as much as you can. To download the question papers, you can visit eduncle.com Here you will also get some best strategies and plans to study for JEE Main and for other competitive exams.
So, nobody is gonna add me , OK, fine by me !
I am in class 9 now and will appear NTSE in 2017-18. Will somebody help me by giving me tips.
Log in to reply
For SST go with NCERT , work hard for MAT (you can use Reasoning book) , and go with your coaching materials for PCM
Log in to reply
If i advice someone for NTSE or kvpy i feel that yeah i have done something in life :P :P .
Log in to reply
@Prakhar Bindal
Me toome too , i'm gonn34130.092018967002103929669877572 give it too , i w34130.092018967002103929669877572nt some tips too
I live in Bhilai and I study at DPS Bhilai
@Aniket Sanghi- I go to Fiitjee as well are the study packages and compendiums sufficient for Bio too or I need any other book
Log in to reply
I guess compendium are more than enough
@Aniket Sanghi- Thanks Bhaiya for your suggestions.Will you suggest me something about how to do well in Fiitjee tests too
Log in to reply
Always Welcome! :)
Study for yourself .... The thing is you should know how to solve questionso not just scoring ... Automatically you will see your Rank increasing . Try to use max time possible in lower classes so that you relief yourself a bit for higher classes.
Log in to reply
Will you suggest me something to do well in JEE pl. ? i'm just expecting 150 in mains :(
Log in to reply
Log in to reply
Log in to reply
Yeah you can! ... At least you can improve many chapters which will increase your rank a lot!
Log in to reply
How relief myself in higher classes should I read any books if yes then which
Log in to reply
These were my suggestions , you should follow the ones those are compatible.
give some advice to me too :) for ntse
Log in to reply
to kyon NTSE ke advice mang rha hai?
Log in to reply
Log in to reply
Log in to reply
Log in to reply
Log in to reply
Log in to reply
Yes there is class limit in NTSE ..
Log in to reply
Log in to reply
Log in to reply
Log in to reply
Log in to reply
@shubham dhull- Which class you are in
What is a slack which you all talk about
Log in to reply
it is a site just like fb to chat , you can talk to girls( if u can find them :P) and have a settlement :)
Log in to reply
ONLY IF U WANT TO DO SO :|
Its like a social media but of your choice . There you have to make a team or get added to one through invitation in email. You can add members to team through there emails. Thats it ... Its not like other social sites where the max world is with you...here you can have only the ones who are in your team.
@aniket Sanghi - How to prepare for RMO.which books to refer?would I need any extra tuition also except fiitjee
Log in to reply
I was not knowing about RMO so never gave it.... i cant help i guess .... also you can question or answer me by just clicking the reply button in any of my comment , that will automatically send me the message , to reply click on the lower white of the comment , there you will find that a hidden reply button suddenly appear...click it..
If you u dont mind I can help you although this question was not meant for me.basically your mathematical insight should be good enough.the q in rmo need only a little of creative thinking,and sometimes smartness.but a rigorous idea and practice is needed for the subsequent stages.you can referefer to-1)challenge and thrill of pre college maths.2)excursion in mathematics.3)problem solving strategies-Arthur Engel.4)mathematical circles or coxeter for geometry.I do know some more as I was involved in olympiad maths but that's of inmo level.you don't need all but doing some suffices.also love maths and have a quest of problem solving.thanx.
Log in to reply
Thanks spandan where do you live
Log in to reply
Doubt- a container of larger uniform cross sectional area A is resting on a horizontal surface,holds two immiscible liquids of densities d and 2d,each of height H/2.A homogeneous cylinder of length L(L<H/2), cross sectional area A/5 is immersed such that it floats with its axis vertical at liquid-liquid interface with length L/4 in the denser liquid.determine density D of the solid.(answer is in terms of d)
Log in to reply
Just write equation for static equilibrium is total weight is equal to buoyant forces by the two liquids .
Log in to reply
I guess i am getting wrong equation.what will be correct equation
Log in to reply
Where v1 and v2 are volumes immersed inside the liquid.
Log in to reply
Log in to reply
Log in to reply
Hey guys ....Get short notes / formula cheat sheets / previous years advance QUESTIONS / and much more exciting at jeetayyari.blogspot.com
Why is δH=δq(at const pressure) and dU=δq(at const volume)?
@aryan goyat
Log in to reply
u there?
Log in to reply
yes
Log in to reply
Log in to reply
dv=Rdw
adding v to both side v+dv=Rdw+v
v+dv=Rdw+wR
v(after time dt)=w(after time dt)R
Log in to reply
Log in to reply
Log in to reply
Log in to reply
Log in to reply
Log in to reply
Log in to reply
Log in to reply
Log in to reply
Log in to reply
Log in to reply
For Pure rolling on horizontal surface
Case.1 An external force is acting
In This case friction may or may not act. It All depends on the point of application of horizontal force.
Case 2. An External Is Not Acting
In This Case Friction Should Not act if body is continuing pure rolling. Because Friction will provide a and alpha in same direction hence a= R*Alpha can never be true.And once pure rolling started friction Friction will become zero so as the condition remains true (now a and alpha will become zero as there is no force) hence it will continue on to uniform pure rolling ( not accelerated )
External force does not includes friction
Is This analysis correct?
Log in to reply
Log in to reply
@aryan goyat because of you my rolling concept became clear
Thanks a lotLog in to reply
Log in to reply
Log in to reply
Today Rajdeep Asked me a question in which we were required to compare the acidic strength of H2SO4 , HCl AND H3PO4. I Was quite easily able to tell that H3PO4 would be the weakest acid. but was struck in comparing acidic strength of H2SO4 And HCl. i searched internet and got confused as all give a different answer. can any one please help?
@aryan goyat t @Aniket Sanghi @rohit kumar @Aditya Kumar @Abhineet Nayyar
Log in to reply
i think the book you mentioned above ie solomons can help , checkout the table within it it is H2SO4 which is more stronger.(table 3.1 in 10th edition)
Log in to reply
please provide me the link of it.
Log in to reply
That's the problem . I Looked up Wikipedia it says HCl which even confuses me more
Log in to reply
My Book (Cengage (Authentic) ) says H2SO4(pKa = -9) is stronger acid than HCl (pKa = -7)
Different source may give different results as you may know acidity also depends on the solvent.....Like H2SO4 and HCL will differentiate equally in H2O (high dielectric constant) , so you can't use H2O to compare acidity. Similarly may be diff sources are based on diff solvents.
Log in to reply
I Also Thought H2SO4 Because it is diprotic and high resonance on conjugate base let me assume it to be true as it is the same in solomons
Those who love chemistry are invited to try these (BEST OF JEE - ADVANCED)
Hey please can anyone help me with this
The number of normals to the curve 3y^3 = 4x which passes through (0,1) is
Answer Given = 1
My Approach found at slope of normal at any point , wrote its equation and passed through (0,1) . i obtained a 5 degree equation!
Also i entered that equation into wolfram alpha which showed me that only 1 real root exists. How?
@Aniket Sanghi @rohit kumar @Mayank Singh @aryan goyat @Akul Agrawal
Log in to reply
Its quite easy to make graph of y3=34x (I am sure you can do it orally!). And as the function is monotonic, you can easily come to the answer (try once).
Log in to reply
Please can you be more detailed? i realized that function is monotonically increasing as first derivative >0
@Akul Agrawal
Bhaiya i did not got the answer by your method but thought of another way. The 5 degree equation that i was getting was strictly increasing for all real numbers and when x tends - infinity it also tended to -infinity and similar was for +infinity case. Hence it will cross the x axis only once as function is monotonically increasing.
But i want to know your method as it seems quite short . Can you please elaborate ( i have just started learning calculus)
Thanks!
Log in to reply
Log in to reply
Log in to reply
Clearly y=0 (x axis) is normal at origin. Now see how normal changes as we move left or right( it would be easy to see this as function is monotonic). (As we move right, the y- intercept of normal will keep on increasing)
Log in to reply
Hey guys me and aniket had a discussion about this problem . We actually arrived at the answer but the only thing that is left is that we have assumed that atleast one normal will exist in the interval x>0 and y>0 . can we prove that the atleast normal has to exist in this interval? cant it be like no normal can be drawn to the curve
@rohit kumar @Mayank Singh @aryan goyat @Akul Agrawal @Aniket Sanghi
try this https://brilliant.org/problems/no-story-this-time/?ref_id=1178336
Log in to reply
Again let it get some rating :P
Log in to reply
ok ok
without rating , dont we get the credit
Log in to reply
How many of you give full tests of Fiitjee?
Particularly of 25th april 2016
Log in to reply
mention some names to make them aware
Log in to reply
I don't know who all do.
Leave it
Can someone please post a solution to this problem . please!!!!
A spring of mass m is pulled such that a given instant, velocity of both of its end is v in the opposite direction. Find the kinetic energy of the spring.
@Aniket Sanghi @Prakhar Bindal
Log in to reply
mv^2/6?
Log in to reply
Hey are free for next half hour?
I have a problem that's bugging me since evening.
A physics problem.
Log in to reply
Log in to reply
I'll post the prob after 30 mins, havta go out.
Log in to reply
Log in to reply
Log in to reply
Correct! Please give a hint.
You can assume that velocities to vary linearly along the length of spring. Hence consider an element at a distance x from one of the end of the spring , write its velocity as a function of x , Write its kinetic energy as 1/2dmv^2 and integrate from 0 to l to get total kinetic energy.
I Would say to remember this result as it is quite helpful in SHM Problems Involving spring with mass. But Derivation is Important too for Proper Understanding Purposes
You can solve it by integration
Use the property : In spring the velocity of any element dx at a distance x from the point of non-zero velocity is proportional to x.
Now, find the kinetic energy of this element and then integrate to get net kinetic energy.
The property I told you above can easily be proved and I have proved it in one of your doubt discussion
@Harsh Shrivastava
Log in to reply
is'nt my method correct?
Log in to reply
Thanks a ton guyz!
I hope I don't disturb you when I ask my doubts?
Log in to reply
Nahh its my free time. i am watching Taarak Mehta
Log in to reply
I will suggest you to join slack , there you will find many people online every time who will feel it their pleasure to clear yr doubts.
Its link is mentioned in this discussion start.
Log in to reply
i joined it but nothing happens at all .
yes me too mv^2/6 as you must be knowing the contribution of a spring in any energy is m/3. and if we break it in 2 parts , you can do it now hope it helps.
Log in to reply
Why is the contribution m/3?
Log in to reply
@Harsh Shrivastava . I Think we can talk here
Log in to reply
Very bad,126 :(
Wbu, top 50s?
Log in to reply
I Got 15 in ai^2ts 1 . but it does not matter . look at your mistakes and try to improve in next
Log in to reply
Log in to reply
Our next aiits is on 17th and RMO is on 16th, also cm test on 11th and kvpy on 6th novemeber, many exams ahead :p
Log in to reply
Log in to reply
Aspirants who are preparing for IIT JEE, must know about the latest information about JEE Advanced. As per the latest information JEE Advanced 2018 Exam date has been announced. The exam will be conducted on 20 May 2018. Candidates have to boost their preparation level to get good score in exam. Get more information about JEE Advanced from here - https://www.eduncle.com/jee-advanced-exam
Fitjee ki test series ya module agar kise ke pas ho to hme dede mere number hai 9120967530