Target IIT-JEE (Chat Room)


Since we have to compete in jee in an all India level , it is quite obvious that we want the views of others , we want to know about our competitors.

So I have created this as a Communication platform for all those preparing for IIT - JEE.

  • You can talk to the ones personally by mentioning their link. And giving them the time when you will be online .

  • you can ask general questions.

  • you can keep your communication personal by deleting it after your work is over.

  • Anyone can join this chat room and can even invite his friends . For joining just save this note with you (optional).

  • You can even ask your doubts. In any chapter(Restriction :you cannot discuss solution to Brilliant questions here , but you can share the link and ask them to come there )

  • I see ,we don't always get a reply to our question , but if we all be at a single chat room we would definitely get a reply

Since this one is becoming bulkier , here is the continuation Click here

#Algebra

Note by Aniket Sanghi
5 years, 1 month ago

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  Easy Math Editor

This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

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Comments

Doubt:

Please give a hint.

A uniform rid of length L lies on a smooth horizontal table.A particle moving on the table strikes the rod perpendicularly at one end and stops. Find the distance travelled by the center of rod by the time it turns through a right angle.

Harsh Shrivastava - 5 years, 1 month ago

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Use the following equations to find ω \omega :

  1. Conservation of linear momentum

  2. Conservation of angular momentum (about a point just above the COM of the rod, in the air, so that the point taken is stationary wrt ground and there is no angular impulse)

Then use θ=ωt \theta = \omega t to get the time taken by it to rotate through θ \theta

And finally, S=vt S = v t , where v v is the velocity of the COM of the rod after collision, to find the distance travelled

Ashish Gupta - 5 years, 1 month ago

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Ohk got it!

Thanks a ton.

Harsh Shrivastava - 5 years, 1 month ago

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@Harsh Shrivastava RM is tough right? :( I hardly solve few fully independently.

Nihar Mahajan - 5 years, 1 month ago

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@Nihar Mahajan Same here :(

Noatter how hard I try, I can't do physics independently without any aid.

Harsh Shrivastava - 5 years, 1 month ago

@Harsh Shrivastava No problem. Glad to help.

Ashish Gupta - 5 years, 1 month ago

General question:

We all are usually confused whether the book we are referring is nice or not.........especially in the critical month before jee advanced.........let's here share the books we prefer along with a reason why we prefer it

Aniket Sanghi - 5 years, 1 month ago

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Maths - cengage (lot of q to practice along with solutions)

Physics - cengage (lot of q to practice along with their solutions, nice theory )

Chemistry-

Physical- P bahadur (Everything in few pages)

Inorganic - NCERT ( Best explanation)

Organic - Cengage ( Authentic theory)

Aniket Sanghi - 5 years, 1 month ago

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Physics- HC Verma (Most Authentic Theory and No errors at all and best theoretical Problems are framed from It Only) DC Pandey (Practice Nice questions with solutions)

Chemistry- RC Mukherjee (Physical- Has Almost all the variety of problems and important concepts)

Solomon's And fryhle (Organic- Detailed Explanantion and nice subjective problems)

Inorganic- its none of my buisness ! :P (but still i like ncert)

Maths- I dont get time to solve problems of maths from books (my coaching sheets, packages and archive are more than enough i think)

But still i refer to TMH For algebra for some mind bending problems and arihant for calculus for good explanation of concepts

Prakhar Bindal - 5 years, 1 month ago

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@Prakhar Bindal @Prakhar Bindal I have found a mistake in HC Verma.

Saarthak Marathe - 5 years, 1 month ago

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@Saarthak Marathe Can you tell where? ( My Sir told that HC Verma Is 99.9% Authentic)

Prakhar Bindal - 5 years, 1 month ago

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@Prakhar Bindal One is in the capacitor chapter .The other is in the SHM chapter,the question where two wheels are rotating and a rod is placed on it,the direction of rotation is given wrong (this question was copied wrongly from irodov.)

Saarthak Marathe - 5 years, 1 month ago

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@Saarthak Marathe can you tell, which one in capacitor is wrong, i agree with the second one , i solved it from irodov.

A Former Brilliant Member - 4 years, 8 months ago

@Prakhar Bindal @Prakhar Bindal what is the color of the cover page of soloman and fryle

Aniket Sanghi - 5 years, 1 month ago

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@Aniket Sanghi Green

This book

http://www.amazon.in/Solomons-Fryhles-Organic-Chemistry-Advanced/dp/8126541814?tag=googinhydr18418-21

Prakhar Bindal - 5 years, 1 month ago

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@Prakhar Bindal What about the red one?

Aniket Sanghi - 5 years, 1 month ago

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@Aniket Sanghi My teacher Suggested to use this as original solomon's has some portion out of JEE Syllabus. Also he gave us a option between Solomon and Morrison And Boyd. My friends are using Morrison and they are finding that useful. I Also saw the book and seemed nice. Also Similar to solomon morrison has a lot of portion not in our syllabus so our teacher recommended to use solomon only but if not available then he said to go for morrison and boyd

http://www.flipkart.com/organic-chemistry-english-7th/p/itmdmyjz99fnszs6 ]\

Prakhar Bindal - 5 years, 1 month ago

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@Prakhar Bindal What is your position in your class and what is your confidence level in organic

Aniket Sanghi - 5 years, 1 month ago

@Prakhar Bindal @Prakhar Bindal Bhaiya, What about theory of Physical Chemistry? RC Mukherjee has little theory, will it be sufficient with my coaching packages and NCERT?

Pankil Kalra - 5 years, 1 month ago

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@Pankil Kalra Well I Never needed any book for theory in physical. NCERT Is nice. If you want some more theory then i would Suggest to go for OP Tandon Or P Bahadur (OP Tandon's physical is nice DONT Ever buy its organic book it would make your head go round!! )

Prakhar Bindal - 5 years, 1 month ago

@Pankil Kalra P bahadur would be nice for theory

Aniket Sanghi - 5 years, 1 month ago

same here but I prefer Ms Chauhan for organic

Prashant Kr - 5 years, 1 month ago

I would say,

Maths-Cengage(JEE type questions)

Physics-Resnick Halliday,Feynman(awesome concepts),HC Verma(conceptual questions),DC Pandey(JEE type),Irodov,Krotov(for high thinking)

Physical Chemistry-P Bahadur(many problems)

Inorganic Chemistry-JD Lee(concepts),OP Tandon(mostly for facts)

Organic Chemistry-Solomons(concept),Himanshu Pandey(many JEE type questions)

To be honest, for physics, every book copies from Irodov,Krotov,Resnick Halliday(including HC Verma,DC Pandey) so I would suggest to solve many questions from these books even if they are difficult.

Saarthak Marathe - 5 years, 1 month ago

Physics- HC Verma , i.e irodov (sometimes) ,arithant publication by d.b. singh (head of science centre kota) vidyamandir modules, past 37 year iit jee questions, NCERT chemistry- i'm very poor at it, i don't really care but sometimes read my modules. NCERT maths- vidyamandir modules, past 37 year papers , TMH ,NCERT higher algebra (hall and knight) i'm not that much of a studious kid :)

A Former Brilliant Member - 4 years, 8 months ago

Thanks a lot @Aniket Sanghi

Aakhyat Singh - 3 years, 4 months ago

@Aniket Sanghi @Prakhar Bindal Thank you both :D

Pankil Kalra - 5 years, 1 month ago

What is the exam pattern of JEE 2017?

Nihar Mahajan - 5 years, 1 month ago

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you never know jee pattern even 1 day before JEE exam (adv. obviously!)

Akul Agrawal - 5 years, 1 month ago

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Yes you are right. No one expected last year's pattern.

Aditya Kumar - 5 years, 1 month ago

What is the exam pattern of JEE 2020? :P

A Former Brilliant Member - 5 years, 1 month ago

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What is the exam pattern of JEE 2018?

Harsh Shrivastava - 5 years, 1 month ago

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@Harsh Shrivastava It will be online(that's what everyone knows :D) AS OF NOW, IN 2018.

Aakhyat Singh - 3 years, 4 months ago

@Harsh Shrivastava The JEE Main Exam will be conducted on 8TH, 15TH AND ON 16TH April 2018. The mode of examination for JEE Main Examination will be online as well as offline. There will be 90 questions of 360 marks in JEE Main Exam. Only objective type questions will be asked in Paper I. JEE Advanced Exam will be held on 20 May 2018. The exam will be organized in online mode only. The exam will comprise two Papers i.e. Paper I and II. To know more about these exams, you can also visit eduncle.com I hope it helps!

Ravi Mahawar - 3 years, 3 months ago

Is there any PDF or eBook which can help me improve my Coordinate Geometry for JEE Advanced? Since it's right around the corner and is generally where I lose marks in Maths, I'm wondering if there is any such resource or even a good question bank or something of the sort which can help me make it my strong point (most people say it's the easiest part of Maths).

Ashish Gupta - 5 years, 1 month ago

I want to clear a doubt in this question

please read my comment and tell where i am going wrong.

Thanks.

neelesh vij - 5 years, 1 month ago

Salute to the person who got the idea to Cretate this chat room . please can anyone tell the person who created this chat room . a wonderful idea . thank-you this chat room helped me a lot

Sai Kiran - 5 years, 1 month ago

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Thanks! I hope it will be helpful to all :)

Aniket Sanghi - 5 years, 1 month ago

A good mechanics problem :

A weightless rod of length ll with a small load of mass m at the end is hinged at point as shown in the figure and occupies a strictly vertical position, touching a body of mass M. A light jerk sets the system in motion. For what mass ratio M/m will the rod form an angle x=30x = 30 ^{\circ} with the horizontal at the moment of the separation from the body?What will be the velocity u of the body at this moment? Friction should be neglected.

Please help me with this problem.

@shubham dhull @Prakhar Bindal @Aniket Sanghi

Harsh Shrivastava - 4 years, 8 months ago

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M/m = 4 v = (1/2)(gl/2)^0.5

Aniket Sanghi - 4 years, 8 months ago

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why don't u come over slack ?

A Former Brilliant Member - 4 years, 8 months ago

Doubt: A small object is at rest on the edge of a horizontal table. it is pushed in such a way that it falls off the other side of the table, which is 1 m wide, after 2 s. Does the object have wheels?

arpan manchanda - 4 years, 3 months ago

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Average speed = total distance/total time. Therefore the average speed of the object is 1m/2s = 0.5 ms-1. We assume that the frictional force is constant such that the object decelerates uniformly, so we can say that 'average v = 1/2(initial v + final v)' From here, we can see that the initial speed cannot be greater than 1 ms-1, because 'final v' is more than or equal to 0 ms-1.

'Acceleration = (final v - initial v)/t', thus the magnitude of the object's acceleration is at most 0.5 ms-2. Frictional force = uN = umg, so frictional acceleration = F/m = ug, which is at most 0.5 ms-2 in this case. This means that 'u' cannot be greater 0.5/9.81 = 0.05. This is much smaller than the coefficients of friction between ordinary materials, and therefore it is very likely that the object does not slide, but that it has wheels and rolls. [adapted answer from source]

I also came across this question once this was the solution I found

Abhyuday Singh - 4 years, 3 months ago

Doubt : Please suggest some method to proceed-

First excitation potential of a hydrogen like species is 15eV. How can i possibly calculate energy if im given potential?Can someone let me know how to calculate energy of second orbit using this data ?

Ujjwal Rawat - 3 years, 11 months ago

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I guess you know that energy of the n(th) Bohr orbit Is given by,E=13.6(z/n)2eV=E(1)/n2E=-13.6(z/n)^2 eV=E(1)/n^2.Where E(1)E(1) is the energy of the ground state.Hence E(2)=E(1)/4E(2)=E(1)/4.and Thus E(2)E(1)=15E(2)-E(1)=15.Hence E(2)=5eVE(2)=-5eV

Spandan Senapati - 3 years, 11 months ago

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I know that already and you cant take z=1 as its not specified.Secondly,i have to convert potential to energy.Tell me how that is done.Dont just post answers for the sake of it.

Ujjwal Rawat - 3 years, 11 months ago

Invitation to @Prakhar Bindal @Gauri shankar Mishra @Aditya Kumar @aryan goyat @Mayank Singh and all who are interested are welcomed

Aniket Sanghi - 5 years, 1 month ago

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Thats a nice Initiative

Prakhar Bindal - 5 years, 1 month ago

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Great work

Gauri shankar Mishra - 5 years, 1 month ago

@aryan goyat

Prakhar Bindal - 5 years, 1 month ago

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@Calvin Lin @Andrew Ellinor @Ronak Agarwal @Nishant Rai @Sandeep Bhardwaj @ Deepanshu Gupta @David Mattingly

You all are experts and our seniors, We need and expect help from you .............

Aniket Sanghi - 5 years, 1 month ago

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@Aniket Sanghi Sure. Always happy to help :)

Sandeep Bhardwaj - 5 years, 1 month ago

@Adarsh Kumar @Kalash Verma @Nihar Mahajan

Harsh Shrivastava - 5 years, 1 month ago

How is your study going?

Rishabh Deep Singh - 5 years, 1 month ago

Nice

Mayank Singh - 5 years, 1 month ago

Is reading NCERT for inorganic enough?

Aditya Kumar - 5 years, 1 month ago

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We are told that's enough for rest our fiitjee materials fill the vacant spaces

Aniket Sanghi - 5 years, 1 month ago

i dont think so

Mayank Singh - 5 years, 1 month ago

JD LEE + NCERT + Your institute's notes + Previous years papers = total JEE advanced inorganic chemistry

Mayank Singh - 5 years, 1 month ago

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Thanks I was doing JD LEE now. I was not sure whether that level would come. Now I shall read it more seriously.

Aditya Kumar - 5 years, 1 month ago

I have 2 doubts. Firstly, in this Physics question question, the answer comes out as R22Pg3T R^2 \sqrt{\frac{2 P \cdot g}{3T}} , right? Secondly, in this Maths question, is there any better way of solving it other than taking partial derivatives, solving the simultaneous equations in x,yx,y and plugging them in to get the answer?

Ashish Gupta - 5 years, 1 month ago

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For the first one,the answer comes out as R2Pg3T\displaystyle {R}^{2}\sqrt{\frac{Pg}{3T}} because, it is a bubble and as there are two layers, while solving we have to take 22πR2*2\pi*R.

Saarthak Marathe - 5 years, 1 month ago

What is adv.

arpan manchanda - 5 years, 1 month ago

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What are you asking?? Be clear

Aniket Sanghi - 5 years, 1 month ago

A common doubt : How to prepare inorganic chemistry and from where

@Sandeep Bhardwaj

Aniket Sanghi - 5 years, 1 month ago

I see that many students find themselves weak in chemistry , so, let's practice chemistry

A person who will answer the question correctly with its solution will have the right to post the next question, followed by another.and sequence would go on ............

Aniket Sanghi - 5 years, 1 month ago

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1 st question : how many radial nodes are present in the orbital represented as : n = 5 , l = 2 , m = 0.

Aniket Sanghi - 5 years, 1 month ago

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number of radial nodes = n-l-1 = 2.

Number of angular nodes = l = 2

Total Nodes (Excluding the one at infinity) = 4

Total Nodes (Including Infinity one) = n = 5

Prakhar Bindal - 5 years, 1 month ago

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@Prakhar Bindal Wrong answer!

Aniket Sanghi - 5 years, 1 month ago

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@Aniket Sanghi But why?

Prakhar Bindal - 5 years, 1 month ago

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@Prakhar Bindal I think you didn't try my set !

Aniket Sanghi - 5 years, 1 month ago

@Prakhar Bindal dz2 has no nodal planes it has two nodal conical surface..

aryan goyat - 5 years, 1 month ago

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@Aryan Goyat Right! Can you elaborate about nodal conical suface (I would like to know)

Aniket Sanghi - 5 years, 1 month ago

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@Aniket Sanghi i hope you know the shape of 5dz2 orbital just make 2 cones such that it does not touch the electron density. you may google for the pics.

aryan goyat - 5 years, 1 month ago

@Aryan Goyat Can You Please elaborate? and can you tell from where can i learn these things about nodal planes,nodes etc?

Prakhar Bindal - 5 years, 1 month ago

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@Prakhar Bindal i learnt it from J.D.Lee(inorganic chem book)(i have the orange one but if you have black you can post hundreds of question which would have 0 solvers but its not for jee orange one is) but for now you may look "https://www.physicsforums.com/threads/classifying-electron-orbitals-by-nodes.621771/".

aryan goyat - 5 years, 1 month ago

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@Aryan Goyat So should I prefer orange or the black one for jee or is their any other (JD lee) please can you share the

@aryan goyat @Mayank Singh

Aniket Sanghi - 5 years, 1 month ago

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@Aniket Sanghi if you love doing chemistry and really enjoy the inorganic part go for black i also wanted to have it but i didn't knew at that time. But it has some topics which jee does not test.

aryan goyat - 5 years, 1 month ago

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@Aryan Goyat I want to be confined with jee syllabus and don't want to miss anything , then which one to prefer

Aniket Sanghi - 5 years, 1 month ago

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@Aniket Sanghi orange one :)

aryan goyat - 5 years, 1 month ago

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@Aryan Goyat And what's your expected score in jee main

Aniket Sanghi - 5 years, 1 month ago

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@Aniket Sanghi i am in 12 now and will appear for jee in 2017.

aryan goyat - 5 years, 1 month ago

@Aniket Sanghi I've black

Mayank Singh - 5 years, 1 month ago

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@Mayank Singh Is that better than orange one? What's your analysis

Aniket Sanghi - 5 years, 1 month ago

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@Aniket Sanghi never ceen the orange

Mayank Singh - 5 years, 1 month ago

@Aryan Goyat I too have orange one :) For JEE

Prakhar Bindal - 5 years, 1 month ago

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@Prakhar Bindal Is the black one better or the orange one?

And were you knowing aryan goyat is of our age (I thought he is 1 year ahead)

Aniket Sanghi - 5 years, 1 month ago

@Prakhar Bindal it's the very basic of nodes , you can find it in the great " NCERT " textbook if you see it my bro.

A Former Brilliant Member - 4 years, 8 months ago

you have asked here radial nodes which is n-l-1 may it be 5z2.

aryan goyat - 5 years, 1 month ago

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@Aryan Goyat What 5z2

Aniket Sanghi - 5 years, 1 month ago

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@Aniket Sanghi its 5dz2 .

aryan goyat - 5 years, 1 month ago

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@Aryan Goyat It is definetely 5dz2 as m =0 is for dz2

Aniket Sanghi - 5 years, 1 month ago

Which Resnick Halliday is better? The one written exclusively for jee advanced or one which is not?

Harsh Shrivastava - 5 years, 1 month ago

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Go for the original one. That'll help you for NSEP+JEE.

Aditya Kumar - 5 years, 1 month ago

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https://www.flipkart.com/physics-volume-i-5th-english/p/itmdytmvygedvpch?pid=9788126510887&lid=LSTBOK9788126510887QNNK0T

Is this good?

Harsh Shrivastava - 5 years, 1 month ago

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@Harsh Shrivastava I have Resnik Walker Hallinday. This is different. I have an old book. So I don't know about the new one.

Aditya Kumar - 5 years, 1 month ago

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@Aditya Kumar OK so do you find it useful?

If you have few mins to spare, can you please give me a review about your book? Thanks!

Harsh Shrivastava - 5 years, 1 month ago

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@Harsh Shrivastava Yes it was useful only for theory. Good for clearing concepts.

Aditya Kumar - 5 years, 1 month ago

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@Aditya Kumar Ohk thanks! Clearing of concepts is what I need!

Harsh Shrivastava - 5 years, 1 month ago

Best is Resnick Halliday Crane ( I will not suggest Walker neither do I criticise it).

Akul Agrawal - 5 years, 1 month ago

i want to invite the most intelligent person here but i hope he comes(he is not much active here!) : @Rajbir Malik

A Former Brilliant Member - 4 years, 7 months ago

Hi.😇

Rajbir Malik - 4 years, 7 months ago

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Welcome ( Late response I know ! :P)

Aniket Sanghi - 4 years, 7 months ago

I am just plain regular math lover. Not much....😅 I am not preparing for the JEE, but would love to be the part of the discussion. ( I am an army cadet! )😁

Rajbir Malik - 4 years, 7 months ago

@Aniket Sanghi @shubham dhull @Prakhar Bindal Can i also join your chat room?

If yes, then please tell me how?

Harsh Shrivastava - 4 years, 7 months ago

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i have deleted my account there as i thought i am not doing justice to myself, watching po** every time and the spending time, chatting with people, whenever i was not doing that "thing mentioned above" . i feel pity when i think where i have fallen from a state science Olympiad topper to my current state . sorry for saying it here but i think you r my friends and i can let all my feeling with you ! :(

A Former Brilliant Member - 4 years, 7 months ago

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It is not too late, you can mend yourself, i have seen many people mending their ways and being back on track.May God be with you !

Harsh Shrivastava - 4 years, 7 months ago

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@Harsh Shrivastava thnx bro...... word like these give me some motivation (eve though i think the ditch in which i have fallen is too deep to come out of :(

A Former Brilliant Member - 4 years, 7 months ago

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@A Former Brilliant Member Tujhe maine kitni baar kaha hai ek test tera fait decide nahi kar sakta!

Prakhar Bindal - 4 years, 7 months ago

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@Prakhar Bindal Hey Prakhar bhaiya, any last moment advice for KVPY?

Please give some tips on how to solve paper?

Thanks!

Harsh Shrivastava - 4 years, 7 months ago

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@Harsh Shrivastava It gives you a feeling of proudness when someone seeks an advice for you (yes i have done something) :P.

For your question i would rather say solving chemistry and bio first (they wont consume more than 30 minutes). the two markers are also theoretical . either you know or you dont. its not a good idea to spend time on thinking biology questions if you dont know the solution.

Then i would say move to physics or maths (personal choice) . i did physics coz i knew that i was strong at maths and it will take my rank up .

I Finished physics in about 45 minutes (including 2 markers). i was left with 1 hour 45 minutes of which i devoted 1 hour 30 minutes to maths thinking twice checking each step . it was also fruitful i got a perfect score 25/25 in maths

Then in remaining 15 minutes i had a good look at the whole paper (made some intelligent guesses and 2-3 i did by tukabazi)

All the best! :)

Prakhar Bindal - 4 years, 7 months ago

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@Prakhar Bindal Thanks.

Harsh Shrivastava - 4 years, 7 months ago

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@Harsh Shrivastava i expect that you might have seen last year's paper. i honestly finished maths in 40 minutes (it was quite easy). just i checked my steps to avoid any silly errors!.

Prakhar Bindal - 4 years, 7 months ago

@A Former Brilliant Member Be with good,motivated company.Change yourself now!Or else regret rest of your life!

Consult your parents if needed.See you can come out of the dictch, since if you could not come out, then you might have not regretted.

But you are regretting and that's a positive sign and it means that you can recover back to your normal studies! :)

You just need to be in discipline for 1 week and then you will automatically be normal.

Its is never too late.

Be engaged in fruitful activities all day.

Thanks for reading this LONG post :P

Cheers!!

(I may sound an old teacher but i like to spread motivation, my freinds call me motivator baba :P)

Harsh Shrivastava - 4 years, 7 months ago

Which chat room are you talking about , the one I mentioned above?

Aniket Sanghi - 4 years, 7 months ago

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Yes, when i click on join it says account disabled.

Harsh Shrivastava - 4 years, 7 months ago

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@Harsh Shrivastava Give me your email

Aniket Sanghi - 4 years, 7 months ago

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@Harsh Shrivastava Check your email

Aniket Sanghi - 4 years, 7 months ago

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@Aniket Sanghi Thanks.

Harsh Shrivastava - 4 years, 7 months ago

Plz add me too 😅

Nihar Mahajan - 4 years, 7 months ago

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No i'll not add u :P

Harsh Shrivastava - 4 years, 7 months ago

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@Harsh Shrivastava .... Says the motivation baba ;P

Nihar Mahajan - 4 years, 7 months ago

I'll add you tmmrw k?

Harsh Shrivastava - 4 years, 7 months ago

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@Harsh Shrivastava where ?

A Former Brilliant Member - 4 years, 7 months ago

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@A Former Brilliant Member Slack iitjee channel

Harsh Shrivastava - 4 years, 7 months ago

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@Harsh Shrivastava Ohk . i am also not there can you add me too?

Prakhar Bindal - 4 years, 7 months ago

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@Prakhar Bindal kk

Harsh Shrivastava - 4 years, 7 months ago

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@Harsh Shrivastava My email is

[email protected]

Prakhar Bindal - 4 years, 7 months ago

@Harsh Shrivastava Anytime before JEE 2018 (LOL)

Nihar Mahajan - 4 years, 7 months ago

How do I increase my problem solving speed?

Swapnil Das - 4 years, 7 months ago

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If you are preparing for JEE Main 2018 Exam and in need to boost your speed for solving the questions, then one of the best option is attempting JEE Main previous year question papers as much as you can. To download the question papers, you can visit eduncle.com Here you will also get some best strategies and plans to study for JEE Main and for other competitive exams.

Ravi Mahawar - 3 years, 2 months ago

So, nobody is gonna add me , OK, fine by me !

A Former Brilliant Member - 4 years, 7 months ago

I am in class 9 now and will appear NTSE in 2017-18. Will somebody help me by giving me tips.

Abhyuday Singh - 4 years, 4 months ago

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For SST go with NCERT , work hard for MAT (you can use Reasoning book) , and go with your coaching materials for PCM

Aniket Sanghi - 4 years, 4 months ago

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If i advice someone for NTSE or kvpy i feel that yeah i have done something in life :P :P .

Prakhar Bindal - 4 years, 4 months ago

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@Prakhar Bindal give some advice to me too :) for ntse

A Former Brilliant Member - 4 years, 4 months ago

@Prakhar Bindal Me too @Prakhar Bindal

Aakhyat Singh - 3 years, 4 months ago

@Prakhar Bindal Yeah! :)

Aniket Sanghi - 4 years, 4 months ago

me too , i'm gonn34130.092018967002103929669877572 give it too , i w34130.092018967002103929669877572nt some tips too

A Former Brilliant Member - 4 years, 4 months ago

I live in Bhilai and I study at DPS Bhilai

Abhyuday Singh - 4 years, 4 months ago

@Aniket Sanghi- I go to Fiitjee as well are the study packages and compendiums sufficient for Bio too or I need any other book

Abhyuday Singh - 4 years, 4 months ago

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I guess compendium are more than enough

Aniket Sanghi - 4 years, 4 months ago

@Aniket Sanghi- Thanks Bhaiya for your suggestions.Will you suggest me something about how to do well in Fiitjee tests too

Abhyuday Singh - 4 years, 4 months ago

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Always Welcome! :)

Study for yourself .... The thing is you should know how to solve questionso not just scoring ... Automatically you will see your Rank increasing . Try to use max time possible in lower classes so that you relief yourself a bit for higher classes.

Aniket Sanghi - 4 years, 4 months ago

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Will you suggest me something to do well in JEE pl. ? i'm just expecting 150 in mains :(

A Former Brilliant Member - 4 years, 4 months ago

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@A Former Brilliant Member Make your base strong ... work on the chapters where you pillars are not erect ... erect them first , then move on to perfection .

Aniket Sanghi - 4 years, 4 months ago

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@Aniket Sanghi just a last time bothering you , i hear everybody say me " make base strong " , how to do that , nobody told me that , pl. tell something bro :) , i will believe anything you tell me pl. :) and can i doo it now ?

A Former Brilliant Member - 4 years, 4 months ago

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@A Former Brilliant Member Like I give my example to explain - I was not quite strong in heat conduction and Radiation , so I started it from Cengage a few days back and completed from it and then from brilliant until I got satisfaction that it is done! ... In one line - " Work Until Satisfaction ".

Yeah you can! ... At least you can improve many chapters which will increase your rank a lot!

Aniket Sanghi - 4 years, 4 months ago

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@Aniket Sanghi thank you bro

A Former Brilliant Member - 4 years, 4 months ago

How relief myself in higher classes should I read any books if yes then which

Abhyuday Singh - 4 years, 4 months ago

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@Abhyuday Singh First read NCERT of class 11th . For PHY in 9th and 10th , link it with 11th and 12th and learn. For maths you can start learning differenciation and integration if you want . They will support you in PHY.

These were my suggestions , you should follow the ones those are compatible.

Aniket Sanghi - 4 years, 4 months ago

give some advice to me too :) for ntse

A Former Brilliant Member - 4 years, 4 months ago

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to kyon NTSE ke advice mang rha hai?

Prakhar Bindal - 4 years, 4 months ago

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@Prakhar Bindal because i wanna clr it too :)

A Former Brilliant Member - 4 years, 4 months ago

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@A Former Brilliant Member 10th class mein de sakte hai ntse naki 12th

Prakhar Bindal - 4 years, 4 months ago

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@Prakhar Bindal i thought i could give it now too :( can't i give it now seriously ? please tell bhai :\

A Former Brilliant Member - 4 years, 4 months ago

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@A Former Brilliant Member Nope . maine 2 saal pehele clear kra tha !

Prakhar Bindal - 4 years, 4 months ago

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@Prakhar Bindal you r great of-course ,is there any exam which i can give now ? by the way is there a age limit or something like that for NTSE ?

A Former Brilliant Member - 4 years, 4 months ago

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@A Former Brilliant Member ha ha i am not great . .....

Yes there is class limit in NTSE ..

Prakhar Bindal - 4 years, 4 months ago

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@Prakhar Bindal is there any exam which i can give now ?

A Former Brilliant Member - 4 years, 4 months ago

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@A Former Brilliant Member such as NTSE or kvpy , i didn't give them , please tell :\

A Former Brilliant Member - 4 years, 4 months ago

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@A Former Brilliant Member Now , nothing left except entrance exams.....(I guess)

Aniket Sanghi - 4 years, 4 months ago

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@Aniket Sanghi too bad for me :( , thx for telling :) is my age over for KVPY too ?

A Former Brilliant Member - 4 years, 4 months ago

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@A Former Brilliant Member I guess , not yet , you can give it next year too I guess .... ( I was talking about this year that everything over)

Aniket Sanghi - 4 years, 4 months ago

@shubham dhull- Which class you are in

Abhyuday Singh - 4 years, 4 months ago

What is a slack which you all talk about

Abhyuday Singh - 4 years, 4 months ago

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it is a site just like fb to chat , you can talk to girls( if u can find them :P) and have a settlement :)

A Former Brilliant Member - 4 years, 4 months ago

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ONLY IF U WANT TO DO SO :|

Aakhyat Singh - 3 years, 4 months ago

Its like a social media but of your choice . There you have to make a team or get added to one through invitation in email. You can add members to team through there emails. Thats it ... Its not like other social sites where the max world is with you...here you can have only the ones who are in your team.

Aniket Sanghi - 4 years, 4 months ago

@aniket Sanghi - How to prepare for RMO.which books to refer?would I need any extra tuition also except fiitjee

Abhyuday Singh - 4 years, 4 months ago

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I was not knowing about RMO so never gave it.... i cant help i guess .... also you can question or answer me by just clicking the reply button in any of my comment , that will automatically send me the message , to reply click on the lower white of the comment , there you will find that a hidden reply button suddenly appear...click it..

Aniket Sanghi - 4 years, 4 months ago

If you u dont mind I can help you although this question was not meant for me.basically your mathematical insight should be good enough.the q in rmo need only a little of creative thinking,and sometimes smartness.but a rigorous idea and practice is needed for the subsequent stages.you can referefer to-1)challenge and thrill of pre college maths.2)excursion in mathematics.3)problem solving strategies-Arthur Engel.4)mathematical circles or coxeter for geometry.I do know some more as I was involved in olympiad maths but that's of inmo level.you don't need all but doing some suffices.also love maths and have a quest of problem solving.thanx.

Spandan Senapati - 4 years, 4 months ago

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Thanks spandan where do you live

Abhyuday Singh - 4 years, 4 months ago

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@Abhyuday Singh Bhubaneswar.

Spandan Senapati - 4 years, 4 months ago

Doubt- a container of larger uniform cross sectional area A is resting on a horizontal surface,holds two immiscible liquids of densities d and 2d,each of height H/2.A homogeneous cylinder of length L(L<H/2), cross sectional area A/5 is immersed such that it floats with its axis vertical at liquid-liquid interface with length L/4 in the denser liquid.determine density D of the solid.(answer is in terms of d)

Abhyuday Singh - 4 years, 3 months ago

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Just write equation for static equilibrium is total weight is equal to buoyant forces by the two liquids .

Harsh Shrivastava - 4 years, 3 months ago

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I guess i am getting wrong equation.what will be correct equation

Abhyuday Singh - 4 years, 3 months ago

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@Abhyuday Singh mg = V1(d)(3l/4)+ V2(2d)(l/4)

Where v1 and v2 are volumes immersed inside the liquid.

Harsh Shrivastava - 4 years, 3 months ago

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@Harsh Shrivastava Are you sure ? Check out the dimensions to get your mistake! : )

Aniket Sanghi - 4 years, 3 months ago

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@Aniket Sanghi I think the correct equation should be like ADL/5=d(3AL/20+2AL/20)

Abhyuday Singh - 4 years, 3 months ago

@Aniket Sanghi Lol yeah I was sleepy so wrote wrong,instead of (3l/4) and (l/4) , g shud come :P

Harsh Shrivastava - 4 years, 3 months ago

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@Harsh Shrivastava I understand :P

Aniket Sanghi - 4 years, 3 months ago

@Harsh Shrivastava Thank you Bhaiya

Abhyuday Singh - 4 years, 3 months ago

Hey guys ....Get short notes / formula cheat sheets / previous years advance QUESTIONS / and much more exciting at jeetayyari.blogspot.com

Targeting Jee - 3 years, 10 months ago

Why is δH=δq(at const pressure) and dU=δq(at const volume)?

Rajorshi Koyal - 2 years, 10 months ago

@aryan goyat

pankaj gupta - 5 years, 1 month ago

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u there?

pankaj gupta - 5 years, 1 month ago

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yes

aryan goyat - 5 years, 1 month ago

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@Aryan Goyat So My Question is According to you if friction does not act in that case the condition a = R*Alpha wont get satisfied for pure rolling right? . But as the bottom most point is at rest so why would friction act?

pankaj gupta - 5 years, 1 month ago

@Aryan Goyat I Mean to say for pure rolling bottom most point must be at rest wrt the surface it is performing pure rolling also the conditon a = R*Alpha should get satisfied . How can they both be simultaneously True?

pankaj gupta - 5 years, 1 month ago

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@Pankaj Gupta why cannot it be see the what we mean by a=alph*R is dv/dt=R.dw/dt

dv=Rdw

adding v to both side v+dv=Rdw+v

v+dv=Rdw+wR

v(after time dt)=w(after time dt)R

aryan goyat - 5 years, 1 month ago

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@Aryan Goyat Ok . My confusion is basically that during pure rolling we say that point of contact remains at rest hence force of friction should not act but we take in several problems like i gave you the previous one

pankaj gupta - 5 years, 1 month ago

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@Pankaj Gupta then why dont you look at the object just after a time dt you find that the object is not doing pure rolling so here comes friction within a negligible time interval which even we cant measure and we would have to say that both act simultaneously.

aryan goyat - 5 years, 1 month ago

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@Aryan Goyat Ok . In the Football Question We Have said that as pure rolling has started after first collision with rough ground so the bottom most point must have come to rest and hence it will be at rest when it again collides with rough ground. Hence there is no reason why friction must act. Cant we compare the two cases?(This football one and situation that i gave you). here also Once pure rolling started on horizontal surface the bottom point comes to rest hence there is no reason why friction should act

pankaj gupta - 5 years, 1 month ago

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@Pankaj Gupta not after first after second.

aryan goyat - 5 years, 1 month ago

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@Aryan Goyat Yeah i meant first collision with rough ground

pankaj gupta - 5 years, 1 month ago

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@Pankaj Gupta sorry i did not noticed the phrase "rough surface" .

aryan goyat - 5 years, 1 month ago

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@Aryan Goyat no problem i just want your opinion on comparison in between two cases if i apply your explanation to our simple case of pure rolling on horizontal surface

pankaj gupta - 5 years, 1 month ago

@Pankaj Gupta next did you find any horizontal force which is making it out of rolling in time dt.

aryan goyat - 5 years, 1 month ago

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@Aryan Goyat in case of football field just after time t however long or small it may be the sphere will go on pure rolling, however it is not so here even after a small time dt the pure rolling is off.

aryan goyat - 5 years, 1 month ago

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@Aryan Goyat i think i need some rest . i will talk to you tomorrow in this regard as i am feeling exhausted. thanks for taking out your precious time and having discussion in my silly concept

pankaj gupta - 5 years, 1 month ago

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@Pankaj Gupta as much i know "no question is a silly question"

aryan goyat - 5 years, 1 month ago

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@Aryan Goyat I Have Done The Following Analysis.

For Pure rolling on horizontal surface

Case.1 An external force is acting

In This case friction may or may not act. It All depends on the point of application of horizontal force.

Case 2. An External Is Not Acting

In This Case Friction Should Not act if body is continuing pure rolling. Because Friction will provide a and alpha in same direction hence a= R*Alpha can never be true.And once pure rolling started friction Friction will become zero so as the condition remains true (now a and alpha will become zero as there is no force) hence it will continue on to uniform pure rolling ( not accelerated )

External force does not includes friction

Is This analysis correct?

pankaj gupta - 5 years, 1 month ago

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@Pankaj Gupta absolutely correct.

aryan goyat - 5 years, 1 month ago

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@Aryan Goyat Thanks a lot @aryan goyat because of you my rolling concept became clear

pankaj gupta - 5 years, 1 month ago

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@Pankaj Gupta i told you earlier too no need of thanks.

aryan goyat - 5 years, 1 month ago

@Pankaj Gupta Ab to tujhe samajh me aa gaya?

Prakhar Bindal - 5 years, 1 month ago

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@Prakhar Bindal Yes i got it tujhe samjhana hi nahi aata :P

pankaj gupta - 5 years, 1 month ago

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@Pankaj Gupta Maybe i am not good at explaining

Prakhar Bindal - 5 years, 1 month ago

Today Rajdeep Asked me a question in which we were required to compare the acidic strength of H2SO4 , HCl AND H3PO4. I Was quite easily able to tell that H3PO4 would be the weakest acid. but was struck in comparing acidic strength of H2SO4 And HCl. i searched internet and got confused as all give a different answer. can any one please help?

@aryan goyat t @Aniket Sanghi @rohit kumar @Aditya Kumar @Abhineet Nayyar

Prakhar Bindal - 5 years, 1 month ago

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i think the book you mentioned above ie solomons can help , checkout the table within it it is H2SO4 which is more stronger.(table 3.1 in 10th edition)

aryan goyat - 5 years, 1 month ago

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please provide me the link of it.

aryan goyat - 5 years, 1 month ago

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@Aryan Goyat https://www.quora.com/Why-is-hydrochloric-acid-stronger-than-sulphuric-acid-even-though-sulphuric-acid-should-dissociate-to-produce-more-hydrogen-ions

Prakhar Bindal - 5 years, 1 month ago

@Aryan Goyat Common strong acids[edit] This is a list of strong acids with pKa < -1.74, which is stronger than the hydronium ion, from strongest to weakest. Perchloric acid HClO4 (pKa ≈ −10)[5] Hydroiodic acid HI (pKa = −9.3)[2] Hydrobromic acid HBr (pKa = −8.7)[2] Hydrochloric acid HCl (pKa = −6.3)[2] Sulfuric acid H2SO4 (first dissociation only, pKa1 ≈ −3)[6] p-Toluenesulfonic acid (pKa = −2.8) Organic soluble strong acid Methanesulfonic acid (pKa = −1.92) Liquid organic strong acid[7] Almost strong acids[edit] from wikipedia

Prakhar Bindal - 5 years, 1 month ago

That's the problem . I Looked up Wikipedia it says HCl which even confuses me more

Prakhar Bindal - 5 years, 1 month ago

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@Prakhar Bindal Wikipedia is not authentic ,it can be edited!

Aniket Sanghi - 5 years, 1 month ago

My Book (Cengage (Authentic) ) says H2SO4(pKa = -9) is stronger acid than HCl (pKa = -7)

Different source may give different results as you may know acidity also depends on the solvent.....Like H2SO4 and HCL will differentiate equally in H2O (high dielectric constant) , so you can't use H2O to compare acidity. Similarly may be diff sources are based on diff solvents.

Aniket Sanghi - 5 years, 1 month ago

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I Also Thought H2SO4 Because it is diprotic and high resonance on conjugate base let me assume it to be true as it is the same in solomons

Prakhar Bindal - 5 years, 1 month ago

Those who love chemistry are invited to try these (BEST OF JEE - ADVANCED)

Aniket Sanghi - 5 years, 1 month ago

Hey please can anyone help me with this

The number of normals to the curve 3y^3 = 4x which passes through (0,1) is

Answer Given = 1

My Approach found at slope of normal at any point , wrote its equation and passed through (0,1) . i obtained a 5 degree equation!

Also i entered that equation into wolfram alpha which showed me that only 1 real root exists. How?

@Aniket Sanghi @rohit kumar @Mayank Singh @aryan goyat @Akul Agrawal

Prakhar Bindal - 5 years, 1 month ago

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Its quite easy to make graph of y3=43x{ y }^{ 3 }=\frac { 4 }{ 3 } x (I am sure you can do it orally!). And as the function is monotonic, you can easily come to the answer (try once).

Akul Agrawal - 5 years, 1 month ago

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Please can you be more detailed? i realized that function is monotonically increasing as first derivative >0

@Akul Agrawal

Prakhar Bindal - 5 years, 1 month ago

Bhaiya i did not got the answer by your method but thought of another way. The 5 degree equation that i was getting was strictly increasing for all real numbers and when x tends - infinity it also tended to -infinity and similar was for +infinity case. Hence it will cross the x axis only once as function is monotonically increasing.

But i want to know your method as it seems quite short . Can you please elaborate ( i have just started learning calculus)

Thanks!

Prakhar Bindal - 5 years, 1 month ago

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@Prakhar Bindal Prakhar I didid it by graph , I first draw the graph of the eq. Then you can see that the graph changes its concavity at x= 0 so you can easily observe that it can have only one normal at x>0 (graph is monotonically increasing)

Aniket Sanghi - 5 years, 1 month ago

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@Aniket Sanghi What is relation between monotonicity and normals? . why will it have only one normal for x> 0 please explain

Prakhar Bindal - 5 years, 1 month ago

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@Prakhar Bindal Graph

Clearly y=0 (x axis) is normal at origin. Now see how normal changes as we move left or right( it would be easy to see this as function is monotonic). (As we move right, the y- intercept of normal will keep on increasing)

Akul Agrawal - 5 years, 1 month ago

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@Akul Agrawal but x axis does not pass through (0,1)

Prakhar Bindal - 5 years, 1 month ago

Hey guys me and aniket had a discussion about this problem . We actually arrived at the answer but the only thing that is left is that we have assumed that atleast one normal will exist in the interval x>0 and y>0 . can we prove that the atleast normal has to exist in this interval? cant it be like no normal can be drawn to the curve

@rohit kumar @Mayank Singh @aryan goyat @Akul Agrawal @Aniket Sanghi

Prakhar Bindal - 5 years, 1 month ago

try this https://brilliant.org/problems/no-story-this-time/?ref_id=1178336

Mayank Singh - 5 years, 1 month ago

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Again let it get some rating :P

Prakhar Bindal - 5 years, 1 month ago

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ok ok

Mayank Singh - 5 years, 1 month ago

without rating , dont we get the credit

Aniket Sanghi - 5 years, 1 month ago

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@Aniket Sanghi u get 100 points

Mayank Singh - 5 years, 1 month ago

How many of you give full tests of Fiitjee?

Particularly of 25th april 2016

Mayank Singh - 5 years, 1 month ago

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mention some names to make them aware

Aniket Sanghi - 5 years, 1 month ago

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I don't know who all do.

Leave it

Mayank Singh - 5 years, 1 month ago

Can someone please post a solution to this problem . please!!!!

Gauri shankar Mishra - 5 years, 1 month ago

A spring of mass m is pulled such that a given instant, velocity of both of its end is v in the opposite direction. Find the kinetic energy of the spring.

@Aniket Sanghi @Prakhar Bindal

Harsh Shrivastava - 4 years, 8 months ago

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mv^2/6?

Prakhar Bindal - 4 years, 8 months ago

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Hey are free for next half hour?

I have a problem that's bugging me since evening.

A physics problem.

Harsh Shrivastava - 4 years, 8 months ago

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@Harsh Shrivastava i can help if you want !

A Former Brilliant Member - 4 years, 8 months ago

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@A Former Brilliant Member Sure!Thanks!

I'll post the prob after 30 mins, havta go out.

Harsh Shrivastava - 4 years, 8 months ago

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@Harsh Shrivastava ok i'll be waiting uptill then

A Former Brilliant Member - 4 years, 8 months ago

@Harsh Shrivastava i think i have waited much than you said

A Former Brilliant Member - 4 years, 8 months ago

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@A Former Brilliant Member Sorry bro, net was down.

Harsh Shrivastava - 4 years, 8 months ago

@Harsh Shrivastava Sorry but i am a bit busy these days (AIITS This monday + revision of class 11) . you can post here i will do as soon as i get some more time

Prakhar Bindal - 4 years, 8 months ago

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@Prakhar Bindal No prob :)

Harsh Shrivastava - 4 years, 8 months ago

Correct! Please give a hint.

Harsh Shrivastava - 4 years, 8 months ago

You can assume that velocities to vary linearly along the length of spring. Hence consider an element at a distance x from one of the end of the spring , write its velocity as a function of x , Write its kinetic energy as 1/2dmv^2 and integrate from 0 to l to get total kinetic energy.

I Would say to remember this result as it is quite helpful in SHM Problems Involving spring with mass. But Derivation is Important too for Proper Understanding Purposes

Prakhar Bindal - 4 years, 8 months ago

You can solve it by integration

Use the property : In spring the velocity of any element dx at a distance x from the point of non-zero velocity is proportional to x.

Now, find the kinetic energy of this element and then integrate to get net kinetic energy.

The property I told you above can easily be proved and I have proved it in one of your doubt discussion

@Harsh Shrivastava

Aniket Sanghi - 4 years, 8 months ago

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is'nt my method correct?

A Former Brilliant Member - 4 years, 8 months ago

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@A Former Brilliant Member You are Using one result to prove another. He wants the proof of the result you are preassuming to be true!

Prakhar Bindal - 4 years, 8 months ago

Thanks a ton guyz!

I hope I don't disturb you when I ask my doubts?

Harsh Shrivastava - 4 years, 8 months ago

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Nahh its my free time. i am watching Taarak Mehta

Prakhar Bindal - 4 years, 8 months ago

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@Prakhar Bindal if it's your free time bonus: prove the result i am using.

A Former Brilliant Member - 4 years, 8 months ago

I will suggest you to join slack , there you will find many people online every time who will feel it their pleasure to clear yr doubts.

Its link is mentioned in this discussion start.

Aniket Sanghi - 4 years, 8 months ago

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i joined it but nothing happens at all .

A Former Brilliant Member - 4 years, 8 months ago

yes me too mv^2/6 as you must be knowing the contribution of a spring in any energy is m/3. and if we break it in 2 parts , you can do it now hope it helps.

A Former Brilliant Member - 4 years, 8 months ago

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Why is the contribution m/3?

Harsh Shrivastava - 4 years, 8 months ago

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@Harsh Shrivastava because of its twists and turns, the linear contribution of mass is only m/3 , you can google if there is any proof but it would be great if you try to remember it . hope it helps !

A Former Brilliant Member - 4 years, 8 months ago

@Harsh Shrivastava . I Think we can talk here

Prakhar Bindal - 4 years, 8 months ago

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Very bad,126 :(

Wbu, top 50s?

Harsh Shrivastava - 4 years, 8 months ago

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I Got 15 in ai^2ts 1 . but it does not matter . look at your mistakes and try to improve in next

Prakhar Bindal - 4 years, 8 months ago

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@Prakhar Bindal Of class 11

Prakhar Bindal - 4 years, 8 months ago

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@Prakhar Bindal Thanks for encouragement.

Our next aiits is on 17th and RMO is on 16th, also cm test on 11th and kvpy on 6th novemeber, many exams ahead :p

Harsh Shrivastava - 4 years, 8 months ago

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@Harsh Shrivastava Ohh go ahead. KVPY Isn't a big deal but bio can trouble you a lot (i remember scoring about 7 marks out of 25 in aptitude test which was primarily responsible for not so good rank in KVPY)

Prakhar Bindal - 4 years, 8 months ago

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@Prakhar Bindal Thanks.

Harsh Shrivastava - 4 years, 8 months ago

Aspirants who are preparing for IIT JEE, must know about the latest information about JEE Advanced. As per the latest information JEE Advanced 2018 Exam date has been announced. The exam will be conducted on 20 May 2018. Candidates have to boost their preparation level to get good score in exam. Get more information about JEE Advanced from here - https://www.eduncle.com/jee-advanced-exam

Ravi Mahawar - 3 years, 8 months ago

Fitjee ki test series ya module agar kise ke pas ho to hme dede mere number hai 9120967530

Ram Sita - 2 years, 11 months ago
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