Ternary contains 0?

Is there any simple way to check if a number, when represented in ternary (base-3), contains a 0? Trivial 0's, like in 0212, obviously don't count. Is this even possible in bases other than binary?

Easy Math Editor

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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

There is one way for the first digit: if the number is divisible by the base, the first digit is zero.

Jeff Giff - 9 months, 3 weeks ago

I know that, but are there any properties that all ternary numbers with a zero fulfill, but those without don't? For example, all binary numbers without a zero are of the form (2^n)-1.

Akshaj Gopalakrishnan - 9 months, 3 weeks ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$