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Comments
X went first. I'm making the assumption that
1. Both will complete your 3-in-a-line if they can (and hence win)
2. Both will play to prevent the other from getting a 3-in-the-line (and hence not lose immediately)
3. Other than that, you are allowed to play in any way.
If O went first, then by his second turn he must have obtained 2 in a row (since any 2 of the 3 O's are in a line). This means that X will need to block it (since X cannot win in the 2nd turn), thus the first 2 O's placed must be in the middle column (the order doesn't matter), and the 2nd X placed must be the top middle one. Hence, the third O placed must be in the bottom left corner, after which X will need to play in either the top right or bottom right to prevent the 3-in-a-line.
Hence, we are left with the case that X went first. We also need to verify that a sequence of moves is possible. See Aditya's comment.
It is "x's" turn.
I tried most of the moves that would lead to this and I could narrow down to one solution, where X first plays In the 1st row 2nd column, then zero is made in the centre. Next, x is made in the 2nd row 1st column and zer0 in the 3rd row 2nd column. Finally, x is played in the 1st box and the zero in the 3rd row 1st column. This might not be the perfect solution though.
If this is a classical tic-tac-toe,I think the moves that you have suggested in your solution is a bit illogical .They are not looking for a chance to get themselves in a row of 3 same symboles.
Then any two players playing rationally would never arrive at this situation. Though it is important to note that sometimes negligence can lead to this pattern. Methinks.
think about it like this x has one position from where he can win but but 0 has two winning positions.........so if 0 had to win he would have until now......but its not.....so naturally it is 0's turn....aye?
Well see,game starts with X,then O and again X and so on...
At any instant of the game Number of O CAN NEVER BE MORE THAN X,here number of X and O is same so it has to be X's turn
its X turn as it the player of X will not let the O player to get both ways to win without closing one path (diagonal or horizontal). Logically its X's turn
whoever went first - it's his turn
now we have to decide who went first
if we assume that x was not dumb 0 cannot possibly go first - i tried every possible move with 0 starting first and every time got to a situation where the THIRD move of x must be to block 0's next move which is obviously not the case here so we can safely assume that x went first and it's his turn
actually in both the players playing have made the blunder because 1 of the two players actually had a chance to win the game but refuse to do so. So, both x and o can the next turn
cross, my moves... 1st cross of second row, then zero of third row & second column, then cross of 1st row & 2nd column, then zero of middle one, then cross then zero ...so, next chance cross....too lazy to type reason
It has to be 'x' simply because any two of the three circles force the 'x' player to respond to it, assuming both players are playing 'reasonably' and not just filling up squares randomly - thus after the circle player's second move, 'x' must respond; after the circle player's third move, the X player must respond again; looking at the board, X has only responded once by blocking a line of three; its thus his turn again
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*or_italics_**bold**or__bold__paragraph 1
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[example link](https://brilliant.org)> This is a quote# I indented these lines # 4 spaces, and now they show # up as a code block. print "hello world"\(...\)or\[...\]to ensure proper formatting.2 \times 32^{34}a_{i-1}\frac{2}{3}\sqrt{2}\sum_{i=1}^3\sin \theta\boxed{123}Comments
X went first. I'm making the assumption that 1. Both will complete your 3-in-a-line if they can (and hence win) 2. Both will play to prevent the other from getting a 3-in-the-line (and hence not lose immediately) 3. Other than that, you are allowed to play in any way.
If O went first, then by his second turn he must have obtained 2 in a row (since any 2 of the 3 O's are in a line). This means that X will need to block it (since X cannot win in the 2nd turn), thus the first 2 O's placed must be in the middle column (the order doesn't matter), and the 2nd X placed must be the top middle one. Hence, the third O placed must be in the bottom left corner, after which X will need to play in either the top right or bottom right to prevent the 3-in-a-line.
Hence, we are left with the case that X went first. We also need to verify that a sequence of moves is possible. See Aditya's comment.
It is "x's" turn. I tried most of the moves that would lead to this and I could narrow down to one solution, where X first plays In the 1st row 2nd column, then zero is made in the centre. Next, x is made in the 2nd row 1st column and zer0 in the 3rd row 2nd column. Finally, x is played in the 1st box and the zero in the 3rd row 1st column. This might not be the perfect solution though.
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If this is a classical tic-tac-toe,I think the moves that you have suggested in your solution is a bit illogical .They are not looking for a chance to get themselves in a row of 3 same symboles.
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Then any two players playing rationally would never arrive at this situation. Though it is important to note that sometimes negligence can lead to this pattern. Methinks.
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Ok,got it.
X
the person who played first
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you have to either answer zero or cross. state your reason as well.
X's turn. I tried to simulate it as if O had started but if that was the case O's moves would not be logical.
think about it like this x has one position from where he can win but but 0 has two winning positions.........so if 0 had to win he would have until now......but its not.....so naturally it is 0's turn....aye?
calvin sir can you help us with this?
of 0 one
Well see,game starts with X,then O and again X and so on... At any instant of the game Number of O CAN NEVER BE MORE THAN X,here number of X and O is same so it has to be X's turn
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Dude, 'x' need not be first.
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yes..the game stars with X..
its X turn as it the player of X will not let the O player to get both ways to win without closing one path (diagonal or horizontal). Logically its X's turn
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Well talking about logic...X gave a chance to O for wining.. :)
0 in that game fist user can be enered in a squre box first so enter 0 in next
its x's turn
whoever went first - it's his turn now we have to decide who went first if we assume that x was not dumb 0 cannot possibly go first - i tried every possible move with 0 starting first and every time got to a situation where the THIRD move of x must be to block 0's next move which is obviously not the case here so we can safely assume that x went first and it's his turn
arent we assuming that the players dont do a one move blunder??
next turn is of X bcuz he is not a fool to loose such an easy game
it seems 0 has made a riddle 2 win the game becuz next is of X but unfortunately X may win hence next turn is of X
I guess 0 because starting with the middle is usually the best first move in tic-tac-toe. Just based on common strategies used in this game.
actually in both the players playing have made the blunder because 1 of the two players actually had a chance to win the game but refuse to do so. So, both x and o can the next turn
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They refused to do so in the previous steps
I agree. Got the same answer.
Case chase ! , I will scan and give you my solution today !
its turn of player using 0 symbol
i hv read a similar prob in a puzzle book...
cross, my moves... 1st cross of second row, then zero of third row & second column, then cross of 1st row & 2nd column, then zero of middle one, then cross then zero ...so, next chance cross....too lazy to type reason
It has to be 'x' simply because any two of the three circles force the 'x' player to respond to it, assuming both players are playing 'reasonably' and not just filling up squares randomly - thus after the circle player's second move, 'x' must respond; after the circle player's third move, the X player must respond again; looking at the board, X has only responded once by blocking a line of three; its thus his turn again
(Was wrong initially; edited)
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What if it is the opposite way round??
x as usually x starts and they have 3 turns each