The AF Problem

                        If something over 0 is undefined, and if a part of an equation satisfies this condition, and if x=2 is just equal to 1/x=1/2 by cross-multiplying, then (x ^ { 3 } + y ^ { 3 } ) = 0 is equal to 1 / ( x ^ { 3 } + y ^ { 3 } ) = 1/0 by cross-multiplying giving and equation of 1 / ( x ^ { 3 } + y ^ { 3 } ) - 1/0 = 0; after doing least common denominator the result would be [ 0 - ( x ^ { 3 } + y ^ { 3 })] / 0 =0 which is - ( x ^ { 3 } + y ^ { 3 } ) /0 = 0, but it should not be equal to zero but undefined? Though if you solve it properly there are many solutions for this. Does it mean that all equations equal to 0 is undefined at the same time having a solution set? If not please explain why.

#NumberTheory #Problem

Easy Math Editor

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Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$