The Crown Puzzle

Okay, I found this problem on the internet, so its obviously not original, but its really tricky, and I liked it a lot, even though its pretty simple. Here it is -

So, I will be posting the solution below shortly. If you got this right in the first try and didn't get confused, share it in the comments. If you have a solution that is different than what I have given, please share that too. That's all folks...


#Logic

Note by A Former Brilliant Member
7 months, 3 weeks ago

No vote yet
1 vote

  Easy Math Editor

This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.

When posting on Brilliant:

  • Use the emojis to react to an explanation, whether you're congratulating a job well done , or just really confused .
  • Ask specific questions about the challenge or the steps in somebody's explanation. Well-posed questions can add a lot to the discussion, but posting "I don't understand!" doesn't help anyone.
  • Try to contribute something new to the discussion, whether it is an extension, generalization or other idea related to the challenge.
  • Stay on topic — we're all here to learn more about math and science, not to hear about your favorite get-rich-quick scheme or current world events.

MarkdownAppears as
*italics* or _italics_ italics
**bold** or __bold__ bold

- bulleted
- list

  • bulleted
  • list

1. numbered
2. list

  1. numbered
  2. list
Note: you must add a full line of space before and after lists for them to show up correctly
paragraph 1

paragraph 2

paragraph 1

paragraph 2

[example link](https://brilliant.org)example link
> This is a quote
This is a quote
    # I indented these lines
    # 4 spaces, and now they show
    # up as a code block.

    print "hello world"
# I indented these lines
# 4 spaces, and now they show
# up as a code block.

print "hello world"
MathAppears as
Remember to wrap math in \( ... \) or \[ ... \] to ensure proper formatting.
2 \times 3 2×3 2 \times 3
2^{34} 234 2^{34}
a_{i-1} ai1 a_{i-1}
\frac{2}{3} 23 \frac{2}{3}
\sqrt{2} 2 \sqrt{2}
\sum_{i=1}^3 i=13 \sum_{i=1}^3
\sin \theta sinθ \sin \theta
\boxed{123} 123 \boxed{123}

Comments

Key:Key: Bluegem=B\color{#3D99F6}Blue gem=B Redgem=R\color{#D61F06}Red gem=R Crown=C\color{#CEBB00}Crown=C Ring=O\color{#EC7300}Ring=O (to make the explanation simpler, I got rid of the + sign so for example of a crown with red gem, I use CR instead, and it's not multiplication.)

Let's list the information: CR + CR + CR = 24\color{#CEBB00} \text{C} \color{#D61F06} \text{R} \color{#333333} \text{ + } \color{#CEBB00} \text{C} \color{#D61F06} \text{R} \color{#333333} \text{ + } \color{#CEBB00} \text{C} \color{#D61F06} \text{R} \color{#333333} \text{ = 24}

BO + BO + CR = 22\color{#3D99F6} \text{B} \color{#EC7300} \text{O} \color{#333333} \text{ + } \color{#3D99F6} \text{B} \color{#EC7300} \text{O} \color{#333333} \text{ + } \color{#CEBB00} \text{C} \color{#D61F06} \text{R} \color{#333333} \text{ = 22}

BB + BB + BO = 19\color{#3D99F6} \text{BB} \color{#333333} \text{ + } \color{#3D99F6} \text{BB} \color{#333333} \text{ + } \color{#3D99F6} \text{B} \color{#EC7300} \text{O} \color{#333333} \text{ = 19}

RR + RR + CR = 16\color{#D61F06} \text{RR} \color{#333333} \text{ + } \color{#D61F06} \text{RR} \color{#333333} \text{ + } \color{#CEBB00} \text{C} \color{#D61F06} \text{R} \color{#333333} \text{ = 16}

  1. For the first line we already know the CR=24÷3=8 \color{#CEBB00} \text{C} \color{#D61F06} \text{R} \color{#333333} = 24 \div 3 = 8 , so CR = 8\color{#CEBB00} \text{C} \color{#D61F06} \text{R} \color{#333333} \text{ = 8}

  2. 22BOBOCR 22 - \color{#3D99F6} \text{B} \color{#EC7300} \text{O} \color{#333333} - \color{#3D99F6} \text{B} \color{#EC7300} \text{O} \color{#333333} - \color{#CEBB00} \text{C} \color{#D61F06} \text{R} =222BO8= 22 - 2\color{#3D99F6} \text{B} \color{#EC7300} \text{O} \color{#333333} - 8 =14÷2= 14 \div 2 BO = 7\color{#3D99F6} \text{B} \color{#EC7300} \text{O} \color{#333333} \text{ = 7}

  3. 197=2BB 19 - 7 = 2BB 12÷4=B 12 \div 4 = B B=3B = 3

  4. 168=2RR16 - 8 = 2RR 8÷4=R 8 \div 4 = R R=2 R =2

Now we get all the information, Let's summarise them:

CR=8CR = 8 BO=7BO = 7 B=3B = 3 R=2R = 2 and we can tell\text {and we can tell} C=6C = 6 O=4 O = 4

Now, for the solution, CB+RB×RO CB + RB \times RO =9+5×6= 9 + 5 \times 6 =39= 39

(I'll add colours later on.)

Half pass3 - 7 months, 3 weeks ago

Log in to reply

You are the first to actually get it right! Lam got it wrong

A Former Brilliant Member - 7 months, 3 weeks ago

Log in to reply

lol I experienced this kind of problem before, but they are harder to guess. Like one of the figures is a shirt with a whistle(barely noticeable), and at the end it ask how much was a shirt.

Half pass3 - 7 months, 3 weeks ago

Log in to reply

@Half Pass3 lol yeah, even I didn't notice before I got to the last line, then it became easy :)

A Former Brilliant Member - 7 months, 3 weeks ago

plz upvote.

Half pass3 - 7 months, 3 weeks ago

Log in to reply

Done!

A Former Brilliant Member - 7 months, 3 weeks ago

That last multiplicative is sneaky sneaky...

alazrabed . - 6 months, 2 weeks ago

Log in to reply

lol yea

A Former Brilliant Member - 6 months, 2 weeks ago

yea, i missed that, otherwise i found this problem rather simple, and was shocked when i got the answer wrong :)

Cuttlefish Rule - 6 months, 1 week ago

I did notice that, but I didn't appreciate the fact that I had to do it all over again. :/

Shane Sarosh - 6 months ago

@Percy Jackson

3RC=24RC=243=82BR+RC=22BR=2282=74BD+BR=19BD=1974=34RD+RC=16RD=1684=2,BC=8+(32)=9,RR=7(32)=6BC+(RD+BD)×RR=9+(2+3)×6=393RC=24\Rightarrow RC=\frac{24}{3}=8\\ 2BR+RC=22\Rightarrow BR=\frac{22-8}{2}=7\\ 4BD+BR=19\Rightarrow BD=\frac{19-7}{4}=3\\ 4RD+RC=16\Rightarrow RD=\frac{16-8}{4}=2, BC=8+(3-2)=9, RR=7-(3-2)=6\\ BC+(RD+BD)×RR=9+(2+3)×6=\boxed{39}

Lâm Lê - 7 months, 3 weeks ago

Log in to reply

lol you just changed it.

Half pass3 - 7 months, 3 weeks ago

Log in to reply

lol

A Former Brilliant Member - 7 months, 3 weeks ago

This is very easy. One crown is 8 because 8x3=24, and one ring is 7 because 22-8=14 and 14/2=7. 19-7=12, so 1 blue diamond=3, since 12/4=3. One crown=8, so one red diamond=2, since 16-8=8 and 8/4=2. Now we can see that one crown without a diamond is 6, since 8-2=6. Also, one ring without a diamond is 4, since 7-3=4. So, one crown with a blue diamond is 9, since 6+3=9. The gems add up to 5, since 3+2=5. One ring with a red diamond is 6, since 4+2=6.

Multiply them together to get 39, since 9 + (5 x 6) = 39.

The answer is 39.

Hermione Granger - 5 months, 3 weeks ago

Log in to reply

You forgot PEDMAS/PODMAS/BODMAS/BEDMAS Granger...Multiplication is done before addition. So its 9+(5×6)9 + (5 \times 6), not (9+5)×6(9+5) \times 6 @Hermione Granger

A Former Brilliant Member - 5 months, 3 weeks ago

Log in to reply

Oh, ok, now your answer makes sense

Hermione Granger - 5 months, 3 weeks ago

I'll change my comment now

Hermione Granger - 5 months, 3 weeks ago

Log in to reply

@Hermione Granger Good :)

A Former Brilliant Member - 5 months, 3 weeks ago

I used code to solve this question: Now that we know the four important values are, we can solve the actual question.

(8-6+4)*(3+2)+(8-2+3), which corresponds to:

(RING-BLUE+RED)*(RED JEWEL + BLUE JEWEL) + (CROWN-RED+BLUE)

So final answer is 39

Anonymous1 Assassin - 5 months ago

Log in to reply

Hmmm, repl.it @Anonymous1 Assassin?

Log in to reply

yep

Anonymous1 Assassin - 5 months ago

Log in to reply

@Anonymous1 Assassin Nice. What's your usrnm?

A Former Brilliant Member - 4 months, 4 weeks ago

Log in to reply

@A Former Brilliant Member Anonymous1 Assassin is my username

Anonymous1 Assassin - 4 months, 3 weeks ago

Log in to reply

@Anonymous1 Assassin Oh, k :)

A Former Brilliant Member - 4 months, 3 weeks ago

Log in to reply

@A Former Brilliant Member bruh lol. ;)

Anonymous1 Assassin - 4 months, 3 weeks ago

I agree that the answer is 39 I found it out this way

RC+RC+RC =RC×3 = 24

3RC = 24

RC÷3 = 24÷3

RC =8

And that crown has a Red gem

Then

BRi+BRi+ C=22

BRi+BRi+8=22

2BRi+8-8=22-8

2BRi=14

2BRi÷2=14÷2

BRi=7

That ring has a blue gem.

2B +2B + BRi =19

4B+7=19

4B+7-7=19-7

4B=12

4B÷4=12÷4

B=3

That is a blue gem

R+R+RC = 16

2R+2R+8-8=16-8

4R=8

4R÷4=8÷4

R=2

That's a red gem

Meaning that the value of a crown with out a red gem is

The value of a crown with a red gem minus the value of a red gem

RC-R=C

8-2=6

C=6

Now a ring with out a gem

BRi-B=Ri

7-3=4

Ri=4

Ri=4 C=6 B=3 R=2

NOOOWW!! The equation

BC+RB×RRi=??

(3+6)+(2+3)×(2+4)

9+5×6

BODMAS

Multiplication before addition

9+(5×6)

9+30

= 39

ANSWER!!!🎆🎆🎇🎇

Sir Livingwood - 5 months ago

Log in to reply

wait wa?

Half pass3 - 5 months ago

Log in to reply

I have added more space, Now do you understand it ?

Sir Livingwood - 4 months, 2 weeks ago

i cant believed i got trolled by the button

NSCS 747 - 7 months, 3 weeks ago

Log in to reply

It isn't troll, its incomplete

A Former Brilliant Member - 7 months, 3 weeks ago

Log in to reply

bruh

NSCS 747 - 7 months, 3 weeks ago

just checked it again... still a troll

NSCS 747 - 7 months, 3 weeks ago

Log in to reply

@Nscs 747 Lol so true @Percy Jackson

Ash Ketchup - 7 months, 3 weeks ago

@Nscs 747 Ya, I trolled you guys, yet gave you the solution, it is do complete now....

A Former Brilliant Member - 7 months, 3 weeks ago

@Nscs 747 hahaha, @NSCS 747 you never know what is inside the buttons!

Half pass3 - 7 months, 3 weeks ago
×

Problem Loading...

Note Loading...

Set Loading...