The integral of x... Simple right?

Today, my friend asked me when to use trig sub in integration. Sarcastically, I said, "always" to which he replied, "Really? What about when you integrate x." So I thought for a second and this is what resulted.

$\displaystyle\int x~dx$

$x=\sin(u)$

$dx=\cos(u)~du$

$\displaystyle\int \cos(u)\sin(u)~du=\frac{1}{2}\displaystyle\int \sin(2u)~du$

$w=2u$

$\frac{1}{4}\displaystyle\int \sin(w) ~dw=-\frac{1}{4} \cos(2u)=-\frac{1}{4}(1-2\sin^2(u))$

$-\frac{1}{4}(1-2x^2)=-\frac{1}{4}+\frac{x^2}{2}+c$

Which, because of the constant of integration, is equivalent to $\frac{x^2}{2}+c$

Moral of the story: always use trig sub.

#Calculus #Trigonometry #School #Classroom #Easymoney

Easy Math Editor

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Comments

Integration of 1 will have more profound effect.

Pi Han Goh - 5 years, 9 months ago

Would it change how you integrated it at all?

Trevor Arashiro - 5 years, 9 months ago

$\int \sin^2 x + \cos^2x \, dx$ .

Calvin Lin Staff - 5 years, 9 months ago

But if you put sin u =x then the x can only take values from -1 to 1

Usama Khidir - 5 years, 9 months ago

This works for integrals like $\displaystyle\int \sin(x) \, dx$ as well.

Pi Han Goh - 5 years, 9 months ago

Hey Trevor! How's it goin'? Are you swamped with homework already? And yeah, trig sub is my fave too :)

Brian Charlesworth - 5 years, 9 months ago

Hey Brian :) Glad to "see" you again. Yes, I'm overflowed with work from school. The main reason I haven't been posting much recently is because I haven't been able to think of many good problems. I'm still solving problems occasionally but there just haven't been many inspirations.

I have around 10 problems just sitting on my phone that I don't wanna post simply because they're not good enough. I guess it's because my problem posting standards have gotten much higher as last year I would have posted them without hesitation. I'll be posting a somewhat useful integration identity soon once I finish all my work that I have to make up from being sick.

Trevor Arashiro - 5 years, 9 months ago

Sorry to hear that you've been sick. :( Catching up can be tough; it always seems to take twice as long to cover the same amount of material. As for posting problems, I basically took the summer off, (although I kept posting solutions now and then), and only posted my first question in two months a few days ago. I'm having issues with inspiration and standards too, but I'm hoping that just getting a few more posted will "prime the pump" and get me back into the flow of things. For you, school takes precedence, as it should, and I assume that any spare time you have for Brilliant gets devoted to your responsibilities as a moderator and collaborator. Anyway, to cheer you up I thought I'd create a problem in your honor. Enjoy. :)

Brian Charlesworth - 5 years, 9 months ago

@Brian Charlesworth – Thanks for the problem. Was fun to solve! Btw, good news and bad news.

Bad news: the note on the integration thingy I was gonna post has been delayed.

Good news: while I was posting it, I found a more general form of the integral and another case that works so I'll have to delay posting the note until I fully figure out this new case.

Trevor Arashiro - 5 years, 9 months ago

@Trevor Arashiro – I'm glad you enjoyed "Trevorsaurus Rex". It took me quite a while to LaTeX that one. :P

I'm continuing to look forward to your next posting; I'm sure that it will be worth the wait. Hope that you've fully recovered from your illness and have caught up with all your coursework. :)

P.S.. How about that Jason Day?!?! He's in another league right now. Fun to watch, and he seems to be such a great guy and role model. I think we may be entering another 'golden age' of men's professional golf with all these young, exceptional players.

Brian Charlesworth - 5 years, 9 months ago

@Brian Charlesworth – Haha, I just looked at the latex. I can't imagine doing that.

The integral note I'm going to post has to do with integrals of the form $\dfrac{1}{x^a \prod (x^b+k)^c}$ and a trick that you can use to get rid of 1, or sometimes (but rarely) more terms in the denominator. You can always get rid of the $x^a$ assuming the the powers in the denominator fit a certain case. If the powers don't fit a the case, then the integral will have logs in its final form. However, I had to delay it because I found another case and I'm working with when a or c are negative (the negative case of a and c will probably be posted in a separate note cuz it changes A LOT).

The 59 was amazing! I unfortunately wasn't watching it but I saw the highlights video (it was practically all 59 shots). Golf is heading towards another surge in popularity, maybe not quite a golden age but with all the young phenoms coming in who knows?

Trevor Arashiro - 5 years, 8 months ago

Can help on this question ? : https://brilliant.org/discussions/thread/extremely-weird-integration/?ref_id=946409

柯南 - 5 years, 9 months ago

You wrote -1/4(cos2u)=1/4(1-2sin^2u) It should be -1/4(cos2u)=-1/4(1-2sin^2u)

Sanchit Nayyar - 5 years, 9 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$