The Monte Hall problem

Think of a gameshow where there are three doors .Behind one there's a goat behind the other two there is a goat . You have chosen a door .Then the host reveals a goat from one of the other two doors . Now two doors remain . The host gives you an option to change your choice. What should you do now?

Easy Math Editor

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Math	Appears as
Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$

Comments

"Behind one there's a goat behind the other two there is a goat." What about the stereotyped nice new car?!

Morgan Blake - 8 years, 3 months ago

flip

Harshit Kapur - 8 years, 3 months ago

switch to the door that was revealed to me. Because I cannot be sure if what lies in the other two doors are actual goats or goat cheese.

Daniel Wang - 8 years, 3 months ago

All of them are goats so no matter what you do you get a goat :)

Eng Ngee H'ng - 8 years, 3 months ago

Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$