the number of solutions of [2x]-3{2x}=1

the number of solutions of [2x]-3{2x}=1? How to solve such problems

#HelpMe! #MathProblem

Note by Priyankar Kumar
7 years, 10 months ago

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Comments

If 2x3{2x}=1\lfloor 2x \rfloor - 3\{2x\} = 1 then 3{2x}=2x13\{2x\} = \lfloor 2x\rfloor - 1 is an integer, so {2x}=0,1/3,2/3\{2x\} = 0,1/3,2/3.

  1. If {2x}=0\{2x\} = 0 then 2x1=0\lfloor 2x\rfloor - 1 = 0, so 2x=1\lfloor 2x\rfloor = 1, and hence 2x=12x=1, so x=1/2x=1/2.

  2. If {2x}=1/3\{2x\} = 1/3 then 2x1=1\lfloor 2x\rfloor - 1 = 1, so 2x=2\lfloor 2x \rfloor = 2, and hence 2x=7/32x=7/3, so x=7/6x=7/6.

  3. If {2x}=2/3\{2x\} = 2/3 then 2x1=2\lfloor 2x\rfloor - 1 = 2, so 2x=3\lfloor 2x \rfloor = 3, and hence 2x=11/32x=11/3, so x=11/6x=11/6.

Mark Hennings - 7 years, 10 months ago

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Thanks

Priyankar Kumar - 7 years, 10 months ago

(I assume that the square and curly brackets represent floor and fractional part function respectively)

I am not the right person to help out in such problems but the following is worth a try. Add and subtract {2x} in the LHS. The equation now becomes 2x-4{2x}=1 or 2x=1+4{2x}. You can now plot a graph to find the number of solutions.

Pranav Arora - 7 years, 10 months ago

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Thanks.

Priyankar Kumar - 7 years, 10 months ago
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