In the picture you see two points "A" and "B" ...Find the equivalent Thevenine's voltage and Equivalent Thevenine's resistance between the two points "A" and "B" and hence find the current through the 2 ohm resistance between the two points "A" and "B".... Please describe by proper picture or give me direction in such a way that it is deciphered easily..Always strictly follow thevenine's theorem...
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basically ,you need to remove the resistance in between points A & B , and then find the OPEN CIRCUIT voltage across A & B...( apply kirchoff law to find V(ab) taking the extreme right loop...as no current flows in the loop,you will get a relation of (2 plus voltage across 4 ohm resistor) as your V(ab)).then find R(th) across terminals A & B.by removing all the voltage sources...then convert the given circuit into a thevenin equivalent and PRESTO!!!! now you can easily calculate the current across 2 ohm resistor...
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give me the results to cross check it...
Basic hints :- As the 10 volt battery provides greater EMF the current will flow in the clockwise direction. Then use the junction rule and loop rule to find the equivalent resistance.