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Math
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2^{34}
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a_{i-1}
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Comments
Well, assuming the room is cuboid in shape, the answer is option D. My reasoning is as follows:
The room has a total volume of 18parcels×(1×1×2)m3/parcel=36m3
You know the floor area is 9m2 and so the height of the room is 36m3÷9m2=4m This invalidates option B, since the height is already known.
Now, since you know that the internal dimensions are natural numbers, they can be (3m×3m) or (1m×9m).
Because you want to fit in cubes of side 1m, these dimensions do not matter, so long as they are natural numbers! The same number of cubes will fit in no matter what the dimensions are - hence, option A in invalidated.
Obviously, option C is useless - I don't care what you fit into the parcels, so long as they don't change its dimensions. And so, by elimination, option D is the right answer.
If you have less than or equal to 36 small parcels, you're good. If you've got more, they won't fit.
Now basically we have the info as follows :-
base area 9 sq. Mts
height 4m
hence total volume of container is 36 cubic mts
Now we have cubes of volume 1 cubic metre ....
we know that no. Of small parcels =
volumr of container ÷ vol. Of small parcel (the cube)
hence in order to have all the parcels to be exactly fit in the container we must know the number of parcels
He packed 18 parcels of 2 cubic metres so now he know both height and floor area of the store now all that matters is how many small parcels are there so he can calculate whether they will fit or not
Easy Math Editor
This discussion board is a place to discuss our Daily Challenges and the math and science related to those challenges. Explanations are more than just a solution — they should explain the steps and thinking strategies that you used to obtain the solution. Comments should further the discussion of math and science.
When posting on Brilliant:
*italics*
or_italics_
**bold**
or__bold__
paragraph 1
paragraph 2
[example link](https://brilliant.org)
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\(
...\)
or\[
...\]
to ensure proper formatting.2 \times 3
2^{34}
a_{i-1}
\frac{2}{3}
\sqrt{2}
\sum_{i=1}^3
\sin \theta
\boxed{123}
Comments
Well, assuming the room is cuboid in shape, the answer is option D. My reasoning is as follows:
If you have less than or equal to 36 small parcels, you're good. If you've got more, they won't fit.
C, the highlighted option is the correct answer btw!
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Now basically we have the info as follows :- base area 9 sq. Mts height 4m hence total volume of container is 36 cubic mts Now we have cubes of volume 1 cubic metre .... we know that no. Of small parcels = volumr of container ÷ vol. Of small parcel (the cube) hence in order to have all the parcels to be exactly fit in the container we must know the number of parcels
He packed 18 parcels of 2 cubic metres so now he know both height and floor area of the store now all that matters is how many small parcels are there so he can calculate whether they will fit or not