This is too hard?

Can you help solving this or is this is not solvable?

\[\large \frac{\displaystyle \sum_{n=1}^{\infty}\left(1+ \left(\frac{1}{2n-\frac{1}{3n+\frac{1}{4n-\frac{1}{5n+_\ddots}}}}\right)^2\right)}{\displaystyle\prod_{n=1}^{\infty} \left(\frac{1}{2n-\frac{1}{4n+\frac{1}{6n-\frac{1}{8n+_\ddots}}}}\right)^2} = \ ?\]

@Brian Charlesworth and @Jon Haussmann any help

Easy Math Editor

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Remember to wrap math in `$` ... `$` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
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`\boxed{123}`	$\boxed{123}$

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Math	Appears as
Remember to wrap math in `\(` ... `\)` or `\[` ... `\]` to ensure proper formatting.
`2 \times 3`	$2 \times 3$
`2^{34}`	$2^{34}$
`a_{i-1}`	$a_{i-1}$
`\frac{2}{3}`	$\frac{2}{3}$
`\sqrt{2}`	$\sqrt{2}$
`\sum_{i=1}^3`	$\sum_{i=1}^3$
`\sin \theta`	$\sin \theta$
`\boxed{123}`	$\boxed{123}$